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Yanka [14]
3 years ago
7

1. Does the point (2, 3) lie on the graph of y=3x-4 ? Explain. (2 points)

Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

No it does not

Step-by-step explanation:

Step 1:

substitute the point (2,3) into the equation for x and y. You will get 3=3(2)-4.

Step 2:

Check if the equation is true using order of operations

If you multiply 3 and 2 you get 6. Next you subtract 4 to get 2

So we have 3 = 2 which is not correct meaning the point does not lie on the graph of y = 3x-4

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Barrett is comparing the membership fees for two museums.The art museum charges a one-time fee of $8.25 plus $2.25 per month. Th
Oksanka [162]

Answer:

$2.50+$1.25 times M

Step-by-step explanation:

$10.75-$8.25=$2.50

$3.50-$2.25=$1.25

$2.50+$1.25=$3.75

As only one-time fee, we cancel out it, then only add on the per-month fee, which is $1.25 every month.

7 0
3 years ago
28 is what % of 20<br><br> 28 is ___% of 20
Greeley [361]
28 is 140% of 20

Hope this helps!
7 0
3 years ago
Is this proportional
love history [14]
What is proportional?
Can you copy and paste the question or link the website?

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6 0
4 years ago
Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the
Ivan

Let L be the line given by the vector equation

(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}.

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by \Pi_1. This is,

\\\\\Pi_1  : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\

We observe that \vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0). Therefore, the vector equation of \Pi_1 defines a plane and \vec{N} is a normal vector to \Pi_1.

 

Finally, the vector equation for the wanted plane, which we denote by \Pi, is

\Pi : (-1,1,2) + r(3,2,4) + s(-3,12,3), r,s \in \mathbb{R} \ .

Thus, if s = 0, then L \subset \Pi and since \vec{N} is parallel to \Pi, then it is perpendicular to \Pi_1.

8 0
3 years ago
area of a square field is 1600 square metre. find the cost of boundary wall if the rate of per metre is Rs. 500​
slavikrds [6]

Answer:

Rs. 20,000

Step-by-step explanation:

the boundary wall will act as a perimeter.

the perimeter of a square field is 4S( S = side)

S x S = area

S2 = area

S =

square root of S2= square root of area

square root of S2 = S

S = square root of area

S = square root of 1600

S = 40m

perimeter = 4 x S

                 = 4 x 40

                 = 160m

1m = rs. 500

40m = <u>40m x rs.500</u>

                     1m

=Rs. 20,000

7 0
3 years ago
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