Select the correct statement

I need help with a 7th grade math problem

barxatty [35]

Answer:

They will make 13.80 dollars

Step-by-step explanation:

so they made 1.80 more

8 0

3 years ago

The triangle shown below has an area of 20 units squared. Find the missing side if the height is 8

Anuta_ua [19.1K]

Answer:

<h3>5 units </h3>

Step-by-step explanation:

Lets keep the missing side as x

And we also know that the area of Triangle is,

$\frac{1}{2} bh$

So taking this into consideration we can write a linear equation like this,

$\frac{1}{2} bh = 20$

Where height is 8,

$\frac{1}{2} \times b \times 8 = 20 \\ 4 \times b = 20 \\ b = \frac{20}{4} \\ b = 5$

So therefore the missing side is 5

7 0

2 years ago

Read 2 more answers

You are attempting to estimate the number of protester marching through the city

Alenkinab [10]

9514 1404 393

Answer:

1000

Step-by-step explanation:

If the number of protesters per minute remains a constant, then you could write the proportion ...

p/12 = 177/2.1

Multiplying by 12 gives ...

p = 12(177/2.1) ≈ 1011.4

Here, minutes are given to 2 significant figures, and the initial count is given to 3 significant figures. The best you can hope for is that your estimate is good to 3 significant figures:

1010 protesters

It is probably sufficient to report the number to 2 significant figures*:

1000 protesters

_____

* Unfortunately, with a number like 1000, the only way you can tell it has 2 significant figures is to report it as 1.0×10³ or 10. hundreds. The trailing zeros are usually not considered significant.

3 0

3 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0

3 years ago

A machine can produce 27 inches of ribbon in 3 minutes.how much ribbon can the machine produce in 1 hour produce in 1 hour?

denis-greek [22]

540 it produce in a hour

7 0

3 years ago