There are 0-14 numbers inclusive, so that means there are 15 scraps of paper.
Probability of getting greater than or equal to six (6, 7, 8, 9, 10, 11, 12, 13, 14) is
(as there are 15 scraps)
so the answer is C.
Answer:
C.3/5
Step-by-step explanation:
The numbers that would fit are 6,7,8,9,10,11,12,13,14. There are 15 numbers int he box. 9/15=3/5
R=7
I hope that help you! :)
Answer:For all the corner points, the maximum is at point (1, 3)
From the graph of the constraints, the corner points of the feasibility region are (0, 0), (0, 10/3), (1, 3), (2, 0)
For (0, 0): p = 0 + 2(0) = 0
For (0, 10/3): p = 0 + 2(10/3) = 20/3 = 6.67
For (1, 3): p = 1 + 2(3) = 1 + 6 = 7
For (2, 0): p = 2 + 2(0) = 2
Therefore, solution = (1, 3)
x<1.912931