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umka2103 [35]
3 years ago
12

Two balls are to be pulled from a vase that contains 7 red balls 9 green balls and 2 black balls. After the first ball Is drawn,

it is not the replaced. What is the probability that two black balls are chosen from the vase?
Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

\frac{1}{153}

Step-by-step explanation:

There are a total of 7 + 9 + 2 = 18 balls in the vase, therefore, when not replacing the first ball, there would be 18 · 17 = 306 ways to pull 2 balls. There are 2 ways to choose the first black ball and then 1 way to choose the second black ball so there are 2 · 1 = 2 ways to choose 2 black balls. Therefore, the probability is 2 / 306 = \frac{1}{153}.

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What is the value of log625^5 converted to a fraction
Anettt [7]

Answer:

1/4

Step-by-step explanation:

625^x = 5

x = 1/4

8 0
3 years ago
Math SAT: Suppose the national mean SAT score in mathematics was 510. In a random sample of 50 graduates from Stevens High, the
sukhopar [10]

Answer:

Mean SAT score for Stevens High graduates are not the same as the national average.    

Step-by-step explanation:

We are given the following information in question:

Population mean, μ = 510

Sample mean, \bar{x} = 501

Sample size, n = 50

Alpha, α = 0.10

Sample standard deviation, s = 30

First, we design the null and the alternate hypothesis

H_{0}: \mu = 510\\H_A: \mu \neq 510

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have,

t_{stat} = \displaystyle\frac{501 - 510}{\frac{30}{\sqrt{49}} } = -2.1 Now,

t_{critical} \text{ at 0.10 level of significance, 49 degree of freedom } = \pm 1.6765 Since,              

t_{stat} < t_{critical}

We reject the null hypothesis and fail to accept it.

We accept the alternate hypothesis and mean SAT score for Stevens High graduates are not the same as the national average.

3 0
3 years ago
In what time the compound amount of Rs 60000 at 10% rate is rs 79860?​
Ksenya-84 [330]

Answer:

P= Rs 60000

A= Rs 79860

T=1 & 1/2 year = 3/2 years

    = 3/2 x 2 = 3 half years

R= ?  

Applying the formula A= P (1+r/100)^T

           79860  = 60000 (1+ r/100)^3

                  79860/60000 = (1+r/100)^3

                  1331/1000 = (1+r/100)^3

root(3)(1331/1000) = (1+r/100)

                     11/10 = 1+r/100

                     11/10 -1 = r/100

                      1/10 = r/100

                       r= 10 %

Step-by-step explanation:

8 0
3 years ago
In the number 7,890,432, name the digit located in each of these positions.
alina1380 [7]
A=4 B=7 C=9 D=3 E=8 F=0
3 0
3 years ago
Read 2 more answers
Solve the equation for a.<br><br> K=4a+9ab
ale4655 [162]

Answer:

a= k/4+9b

Step-by-step explanation:

hope this helps, if not let me know!

3 0
2 years ago
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