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tatuchka [14]
3 years ago
7

(Giving Brailniest) What is 18x+20

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

2(9x+10)

Step-by-step explanation:

18x+20

First, we have to factor. We will have to factor out 2 to get the answer(Factor out 2 from 18x+20).

Answer:

2(9x+10)

Hope this helps!

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Four customers at a grocery store are buying apples. The table shows how many pounds of apples each customer bought and how much
malfutka [58]
Answer is C: 14

Explanation:
On the image added, the pounds of apples is half the cost. So if you would keep that same relationship and add $28.00 to one of the costs the outcome would be 14
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Question Help
lana [24]
B I’m pretty sure I think or 826
4 0
3 years ago
A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th
Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

y = \frac{340110}{1 + 377e^{-0.259t}}

Solving (a): 1998

Year 1998 means that:

t =1998 -  1980

t =18

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*18}}

y = \frac{340110}{1 + 377e^{-4.662}}

y = \frac{340110}{1 + 3.562}

y = \frac{340110}{4.562}

y = 74553 --- approximated

Solving (b): 2003

Year 2003 means that:

t = 2003 -  1980

t =23

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*23}}

y = \frac{340110}{1 + 377e^{-5.957}}

y = \frac{340110}{1 + 0.976}

y = \frac{340110}{1.976}

y = 172120 --- approximated

Solving (c): 2006

Year 2006 means that:

t = 2006 -  1980

t =26

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*26}}

y = \frac{340110}{1 + 377e^{-6.734}}

y = \frac{340110}{1 + 0.4485}

y = \frac{340110}{1.4485}

y = 234802 --- approximated

3 0
3 years ago
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
PLEASEE HELPP MEEEE!!!!!!!!! PLEASEE!!!!!!!!!!!!!!!<br><br> what is the value of x?
andreev551 [17]
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