Answer:
Zero
Step-by-step explanation:
The probability of the ball being red after first selection is = (r) ÷ (r+b)
The probability of the ball being blue after first selection is = (b) ÷ (r+b)
If the ball selected is red, the total number of balls after its returned together with m number of red balls is = r+b+m
The probability of the selection doesn't depend on the second selection, hence condition probability is zero.
However the probability of the second selection depends on the first selection.
For some reason, you're not letting us see the choices,
so I can only give you a most general answer:
-- Any positive fraction greater than 1/2 is closer to 1 than it is to 0 .
-- No negative fraction is.
Answer:
The probability the man was hit by a Blue Cab taxi is 41%.
Step-by-step explanation:
In terms of bayesian probability, we have to calculate P(B|Wr), or, given the witness saw the right colour, the taxi is from the Blue Cab company.
According to Bayes
P(B|Wr) = P(Wr|B)*P(B)/P(Wr)
P(Wr|B) = 0,8
P(B) = 0.15
To calculate P(Wr), or the probability of the witness of guessing right, we have to consider the two possibilities:
1) The taxi is from Blue Cab (B) and the witness is right (Wr).
2) The taxi is from Green Cab (G) and the witness is wrong (Ww).
The total probality of guessing right is
P(B)*P(Wr) + P(G)*P(Ww) = 0.15*0.8 + 0.85*0.2 = 0.29
So we can calculate:
P(B|Wr) = P(Wr|B)*P(B)/P(Wr) = 0.8*0.15/0.29 = 0.41
The probability the man was hit by a Blue Cab taxi is 41%.
Notice the picture below
the lateral area, or just the area of the sides, well, the sides are really just 4 triangles, so just get the area of each, and sum them up, that's the lateral area
