Question

Which shows the image of quadrilateral ABCD after the transformation R0, 90°?

Answer 1

Answer:

The 2nd picture is right answer as it has coordinates as A'(0, 1), B'(1, 0), C'(3, -2), and D'(2, -3). The corresponding answer picture is attached below.

Step-by-step explanation:

As we know that when a figure is rotated 90° counterclockwise about the origin, the side of the points of the figure are switched, and the sign of the y-coordinated is reversed.

Thus, the rule to rotate the point of any figure is rotated 90° counterclockwise about the origin is:

$(x,y)$ → $(-y,x)$

Considering the quadrilateral ABCD in the first figure having the vertices A(-1, 0), B(0, -1), C(-2, -3), and D(-3 , -2) respectively.

So, after quadrilateral ABCD is rotated counterclockwise 90° about the origin,

• A (-1, 0)

A' → (-y,x) = (0,1)

• B(0, -1)

B' → (-y,x) = (1, 0)

• C(-2, -3)

C' → (-y,x) = (3, -2)

• D(-3, -2)

D' → (-y,x) = (2, -3)

So, the coordinates of a quadrilateral ABCD after a rotation of 90° about the origin would be A'(0, 1), B'(1, 0), C'(3, -2), and D'(2, -3) respectively.

Therefore, the 2nd picture is right answer as it has coordinates as A'(0, 1), B'(1, 0), C'(3, -2), and D'(2, -3). The corresponding answer picture is attached below.

Keywords: 90° rotation about the origin, transformation, quadrilateral

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Answer 2

Answer:

The second picture is correct

Step-by-step explanation:

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