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3 years ago

Two more than the quotient of a number and eight is equal to 10

Mathematics

1 answer:

Hunter-Best [27]3 years ago

8 0

2x + 8 = 10
2x + 8 -8=10-8
2x = 2
2x/2 = 2/2
x = 1 ( 2 x 1 + 8 =10)

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What’s the answer in simplified form

Schach [20]

Answer:

Step-by-step explanation:

To solve this correctly, you need to make sure to distribute the negative onto both terms in the second parentheses.

So fully expanded, the problem would be:

2y² + 8y -7 + 3y - 3 = ?

You can easily rearrange the terms, or just do it in your head!

It would become:

2y² + 8y +3y -7 -3

= 2y² + 11y -10

Make sure you keep the terms with different variables separate! I hope this is helpful!

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2 years ago

Consider a data set containing the following values: 70 65 71 78 89 68 50 75 The mean of the preceding values is 70.75. The devi

Leokris [45]

Answer:

If this is the sample data, the sample variance is 125.07 and the sample standard deviation is 11.18

If this is a population data, the population variance is 109.44 and the population standard deviation is 10.46

Step-by-step explanation:

We are given the following data-set:

70, 65, 71, 78, 89, 68, 50, 75

Deviations from the mean

–0.75, –5.75 , 0.25, 7.25, 18.25, –2.75, –20.75, 4.2

Sample size, n = 8

Sample:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

$s = \sqrt{\dfrac{875.5}{7}} = 11.18$

$\text{ Sample variance} = s^2 = 125.07$

Population:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

$\sigma = \sqrt{\dfrac{875.5}{8}} = 10.46$

$\text{ Population variance} = \sigma^2 = 109.44$

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2 years ago