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Minchanka [31]
3 years ago
4

Tsunamis are dangerous! Scientists use the formula s=\sqrt(9.8d) to calculate the speed (s) of the tsunami (in meters per second

) based on the depth (d) of the ocean (in meters). The 9.8 refers to the acceleration of the tsunami due to gravity, in meters per second squared. What is the depth of the ocean (to the nearest meter) if the tsunami is moving at a speed of 320 meters per second?
Mathematics
1 answer:
shtirl [24]3 years ago
5 0
Given that the speed of a tsunami is measured by the formula s= \sqrt{9.8d}.

Given that a <span>tsunami is moving at a speed of 320 meters per second, then we have:

</span>320= \sqrt{9.8d}  \\  \\ \Rightarrow9.8d=320^2=102,400 \\  \\ \Rightarrow d= \frac{102,400}{9.8} =10,448.98\ meters
<span>
Therefore, the depth of the ocean is 10,448.98 meters.</span>
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1. Let the test statistics Z have a standard normal distribution when H0 is true. Find the p-value for each of the following sit
Nonamiya [84]

Answer:

1 a  p -value  =   0.030054

1b   p -value  =   0.0029798

1c  p -value  = 0.0039768  

2a  p-value  =   0.00099966

2b  p-value  =  0.00999706

2c  p-value   = 0.0654412

Step-by-step explanation:

Considering question a

  The alternative hypothesis is H1:μ>μ0

   The test statistics is  z =1.88

Generally from the z-table  the  probability of   z =1.88 for a right tailed test is

    p -value  =  P(Z > 1.88) = 0.030054

Considering question b

  The alternative hypothesis is H1:μ<μ0

   The test statistics is  z=−2.75

Generally from the z-table  the  probability of   z=−2.75 for a left tailed test is

    p -value  =  P(Z < -2.75) = 0.0029798

Considering question c

  The alternative hypothesis is H1:μ≠μ0

   The test statistics is  z=2.88

Generally from the z-table  the  probability of  z=2.88 for a right  tailed test is

    p -value  = P(Z >2.88) =  0.0019884    

Generally the p-value for the two-tailed test is

    p -value  = 2 *  P(Z >2.88) =  2 * 0.0019884    

=> p -value  = 0.0039768  

Considering question 2a

    The alternative hypothesis is H1:μ>μ0

     The sample size is  n=16

     The  test statistic is  t =  3.733

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  16 - 1

=>     df =  15

Generally from the t distribution table  the probability of   t =  3.733 at a degree of freedom of  df =  15 for a right tailed test is  

       p-value  =  t_{3.733 ,  15} = 0.00099966

Considering question 2b

    The alternative hypothesis is H1:μ<μ0

     The degree of freedom is df=23

     The  test statistic is ,t= −2.500

Generally from the t distribution table  the probability of   t= −2.500 at a degree of freedom of  df=23 for a left  tailed test is  

       p-value  =  t_{-2.500 ,  23} = 0.00999706

Considering question 2c

    The alternative hypothesis is H1:μ≠μ0

     The sample size is  n= 7

     The  test statistic is ,t= −2.2500

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  7 - 1

=>     df =  6

Generally from the t distribution table  the probability of   t= −2.2500 at a degree of freedom of  df =  6 for a left   tailed test is  

       t_{-2.2500 , 6} = 0.03272060

Generally the p-value  for t= −2.2500 for a two tailed test is

     p-value  =  2 *  0.03272060 = 0.0654412

4 0
3 years ago
A local little league has a total of 65 players of 20% or left handed how many left-handed players are there
sladkih [1.3K]
Number of players=85 
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85*20/100=
simplify that:
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simplify again:
85*5= 17 
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4 years ago
Sarah opens a small bag of chocolate candies and notices that out of 210 candies, 63 are brown. She assumes the color breakdown
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Answer:

1440

Step-by-step explanation:

We can solve this problem by applying the rule of three.

In fact, we know that:

- Over a package of 210 candies,

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- Here we want to find what is the number of brown candies when the total number of candies contained in the package is 4800

So we can set up the following rule of three:

\frac{x}{4800}=\frac{63}{210}

where

x = number of brown candies when the total number of candies contained in the package is 4800

Solving the expression for x, we find:

x=\frac{63}{210}\cdot 4800 =1440

So, Sarah can expect to find 1440 brown candies in a package of 4800 pieces.

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4 years ago
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wolverine [178]
260 miles x 2 =H<span>e will travel </span>520 miles
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3 years ago
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