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solmaris [256]
4 years ago
14

help me for the points chwck my profile look at my points im rich :) also on my questions i give high points

Mathematics
2 answers:
serg [7]4 years ago
6 0
The answer is B. I’m doing this right now at the moment and i have an A in math class so. Good luck! :)
disa [49]4 years ago
4 0
It would be B, because the two equations are the same answer

You might be interested in
Factor x^3+3x^2+2x completely
Arisa [49]

Answer:

x^3 + 3x^2 + 2x = x(x^2 + 3x + 2)

= x(x^2 + x + 2x + 2)

= x(x(x+1) + 2(x+1))

=x(x+1)(x+2)

Hope this helps!

5 0
3 years ago
PLEASE HELPPPPP
Flauer [41]

Answer:

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

Step-by-step explanation:

DeShawn and Mike each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same store.

Let us represent:

Cost of 1 rose bush = x

Cost of 1 geraniums = y

DeShawn spent $13 on 1 rose bush and 4 geraniums.

x + 4y = 13..... Equation 1

x = 13 - 4y

Mike spent $56 on 10 rose bushes and 3 geraniums.

10x + 3y = 56....... Equation 2

We substitute 13 - 4y for x in Equation 2

10(13 - 4y) + 3y = 56

130 - 40y + 3y = 56

Collect like terms

- 40y + 3y = 56 - 130

-37y = -74

y = -74/37

y = $2

Solving for x

x = 13 - 4y

x = _13 - 4 × $2

x = $13 - $8

x = $5

Therefore,

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

7 0
3 years ago
The quotient of y and 2 is greater than -21
mamaluj [8]

y\div2 > -21\\\\\dfrac{y}{2} > -21\ \ \ \ |\cdot2\\\\y > -42\to y\in(-42,\ \infty)

5 0
3 years ago
A rectangular classroom has an area of 300 square feet. The length of the classroom is 5 feet longer than the width, w. Create a
weqwewe [10]

Answer:

w^2 + 5w = 300

Step-by-step explanation:

A= length x width

A =300

Width = w

length = w + 5

Therefore

300 = (w) x (w + 5)

300 = w^2 + 5w

w^2 + 5w = 300

6 0
3 years ago
Need help please. I don't think this is dimensionally correct however I want to be sure. Please check if s = (2)(u+v)t^2 is dime
irga5000 [103]

Your equation is not dimensionally consistent.

Let L = length and T = time. Without taking into account precise units, you can write velocity as the ratio between some distance L and some time T.

So in terms of these fundamental quantities, your equation can be written as

L = (L/T + L/T)T^2

L = (L + L)T

L = LT

7 0
4 years ago
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