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kakasveta [241]
3 years ago
15

PLEASE HELPPPPP

Mathematics
1 answer:
Flauer [41]3 years ago
7 0

Answer:

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

Step-by-step explanation:

DeShawn and Mike each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same store.

Let us represent:

Cost of 1 rose bush = x

Cost of 1 geraniums = y

DeShawn spent $13 on 1 rose bush and 4 geraniums.

x + 4y = 13..... Equation 1

x = 13 - 4y

Mike spent $56 on 10 rose bushes and 3 geraniums.

10x + 3y = 56....... Equation 2

We substitute 13 - 4y for x in Equation 2

10(13 - 4y) + 3y = 56

130 - 40y + 3y = 56

Collect like terms

- 40y + 3y = 56 - 130

-37y = -74

y = -74/37

y = $2

Solving for x

x = 13 - 4y

x = _13 - 4 × $2

x = $13 - $8

x = $5

Therefore,

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

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3 0
3 years ago
What is the x-intercept of the graph whose equation is y+1=x3 ?
Illusion [34]

Answer:

the equation is y= 3x - 1

Step-by-step explanation:

to find the intersection with x just substitute 0 to Y.

0=3x-1

3x=1

x=1/3

8 0
2 years ago
Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

lim_{x\rightarrow 2^-}f(x)=6

lim_{x\rightarrow 2^+}f(x)=-3

6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0
3 years ago
Read 2 more answers
How do you do this question?
IRINA_888 [86]

Answer:

∑ (-1)ⁿ⁺³ 1 / (n^½)

∑ (-1)³ⁿ 1 / (8 + n)

Step-by-step explanation:

If ∑ an is convergent and ∑│an│is divergent, then the series is conditionally convergent.

Option A: (-1)²ⁿ is always +1.  So an =│an│and both series converge (absolutely convergent).

Option B: bn = 1 / (n^⁹/₈) is a p series with p > 1, so both an and │an│converge (absolutely convergent).

Option C: an = 1 / n³ isn't an alternating series.  So an =│an│and both series converge (p series with p > 1).  This is absolutely convergent.

Option D: bn = 1 / (n^½) is a p series with p = ½, so this is a diverging series.  Since lim(n→∞) bn = 0, and bn is decreasing, then an converges.  So this is conditionally convergent.

Option E: (-1)³ⁿ = (-1)²ⁿ (-1)ⁿ = (-1)ⁿ, so this is an alternating series.  bn = 1 / (8 + n), which diverges.  Since lim(n→∞) bn = 0, and bn is decreasing, then an converges.  So this is conditionally convergent.

5 0
3 years ago
5•11+5•(-4)=5(11-4) wich property?​
ludmilkaskok [199]

Answer:

Step-by-step explanation:

55

3 0
3 years ago
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