Answer : 2446 years.
Explanation :
Length of semi major axis is,
According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.
i.e
where G is gravitational constant
M is mass of sun,
So,
since,
So, orbital period is approximately 2446 years.
B because there is no energy emitted
Answer:
W = 8.92 10² kJ
Explanation:
For this exercise they give us the strength, we must calculate the distance traveled, for this we need the rocket acceleration let's use Newton's second law
F = m a
a = F / m
a = 20 103/1400
a = 14.29 m/s²
With kinematics we can find the distance traveled
² = v₀² + 2 a x
x = ( ²-v₀²) / 2 a
x = (50² -35²) / 2 14.29
x = 1275 / 28.58
x = 44.61 m
Let's calculate the work
W = F.d
The bold is vector; as indicated by the force is in the direction of movement the scalar product is reduced to the ordinary product
W = F d
W = 20 10³ 44.61
W = 8.92 10⁵ J
W = 8.92 10² kJ
The last column in the table lists the location of the three subatomic particles.Protons<span> and </span>neutrons<span> are located in the nucleus, a dense central core in the middle of the atom, while the electrons are located outside the nucleus.</span>
Answer:
(3) mass-energy must be conserved
Explanation:
As we know that gamma rays are mass less and charge less photons which will have sufficient energy.
Now in case of Pair production the gamma photons convert its whole energy into mass by the law of Einstein's mass energy equivalence relation.
As per his relation we can say
here we will have
[tex]\Delta m[\tex] = mass produced
now we also have to think that here the two particles must have a pair of particles and antiparticles so that the combined mass system will have energy equivalent to the energy of gamma photons and also it must follow the conservation of charge
So here it will form an electron and a positron such that total charge will be zero and the energy will be same as energy of gamma photon.