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anzhelika [568]
3 years ago
8

Which sound wave would travel at the fastest speed?.

Physics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

Solids

Explanation:

Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

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3 years ago
which measurment describes the amount of heat needed to raise the temperature of one gram of a material by one degree celsius?
ella [17]

<u>Answer:</u>

Specific Heat

<u>Explanation:</u>

Specific heat is the measurement which describes the amount of heat needed to raise the temperature of one gram of a material by one degree Celsius.

It is the amount of heat required per unit mass to raise the temperature by one degree Celsius. The relationship between heat and the temperature change is usually expressed as shown below:

Q=cmΔT

where Q = heat added,

c= specific heat,

m=mass; and

ΔT = change in temperature


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4 years ago
Mg represents the element
Romashka-Z-Leto [24]

Answer:

Mg is the symbol for Magnesium. Atomic #- 12

Explanation:

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4 years ago
A cube of wood is floating on water. a cube of iron is totally submerged in water. the cubes are equal in volume. which cube has
-BARSIC- [3]
The one that's completely submerged is displacing more water, so the buoyant force on it is greater.
5 0
3 years ago
A solenoid that is 66.1 cm long has a cross-sectional area of 13.8 cm2. There are 1410 turns of wire carrying a current of 8.01
Ymorist [56]

Answer:

a) Energy density of the magnetic field, u = 183.46 J/m³

b) Total energy, E = 0.167 J

Explanation:

a) Number of turns in the solenoid, N = 1410

Area, A = 13.8 cm² = 0.00138 m²

Current, I = 8.01 A

Length of the solenoid, l = 66.1 cm = 0.661 m

Energy density, u is given by the formula u = \frac{B^2}{2 \mu_{0} }

Where B is the magnetic field

The magnetic field in a solenoid is given by the formula, B = \frac{N \mu_{0} I }{l}

B = \frac{1410 * 8.01* \mu_{0}  }{0.661}

B = 17086.38 \mu_0 T

u = \frac{(17086.38 \mu_0)^2}{2 \mu_{0} }\\u = \frac{291944527.29 \mu_0^2}{2 \mu_{0} }\\u = \frac{291944527.29 \mu_0}{2  }\\u = \frac{291944527.29 * 4\pi * 10^{-7} }{2  }\\u = 183.46 J/m^3

b) The total energy = Energy density * Volume

E = u V

Volume = Area * Length

V = Al = 0.00138 * 0.661

V = 0.00091218 m³

E = 183.46 * 0.00091218

E = 0.167 J

4 0
3 years ago
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