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3 years ago

I really need the answer to this ASAP please and thank you.

Mathematics

1 answer:

jenyasd209 [6]3 years ago

3 0

Answer:

Y= 30

Step-by-step explanation:

180-70=110 So now you know what your other two angles add up to.

Take 110 and your two other problems (3y-20) and (y+10)

Substitute y for a random number, as in 30.

Do the math (3(30)-20)

90-20=70 [Now your previous 110 is 40}

Then for the second equation (30+10)= 40

Y=30

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3 years ago

Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As

kakasveta [241]

Answer:

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that $\mu = 13.4224$

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This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985
$

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

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3 years ago

Solve the following equation -2y-6=4

LenKa [72]

Answer:

Y= -5

Explanation: have an amazing day!!

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kenny6666 [7]

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3 years ago

Read 2 more answers

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galben [10]

Answer:

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Step-by-step explanation:

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