The delivery driver has to make deliveries at 5 locations <span>among the 6 locations. </span>This means the order of the probability is important because the route he will take from A to B is different with A to C.
So, you need to use permutation for this problem. The calculation would be:
6P5= 6!/ (6-5)!= 720 different routes
Answer: 700
Step-by-step explanation: 2800 kg / 4 trucks = 700 kg per truck
Answer:
the Slope is 
Step-by-step explanation:
Answer:
b) i) Curve A
ii) - 1.75
iii) x = 1 - √5 or x = 1 + √5
Step-by-step explanation:
b) i) We are given a function y = x² - 2x - 3 and the graph of this function is also shown in the side diagram.
The equation can be rearranged to y = (x - 1)² - 4
⇒ (x - 1)² = y + 4
Therefore, this is an equation of a parabola having the vertex at (1,-4) point and its axis is parallel to the positive y-axis.
So, the curve A represents the equation given. (Answer)
ii) Now, at x = 2.5, f(x) = 2.5² - 2 × 2.5 - 3 = - 1.75 (Answer)
iii) When y = 1, then x² -2x - 3 = 1
⇒ x² - 2x - 4 = 0
⇒ (x - 1)² - 5 = 0
⇒ (x - 1)² - (√5)² = 0
⇒ (x - 1 + √5)(x - 1 - √5) = 0
⇒ x = 1 - √5 or x = 1 + √5 (Answer)
Answer: 40320 sequence to test.
Step-by-step explanation:
we have given the following data:
No of wires which need to be attached to a circuit board = 8
What We need to find is the number of possible sequences of assembly that must be tested.
Using our multiplication rule of counting we arrive at,
Number of possible sequences of assembly is given by
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
= 40320
i.e. there are 8 choices for the first wire, 7 choices for the second wire, 6 choices for the third wire, 5 choice for the fourth wire same till the 8th wire.
Hence, there are 40320 possible sequences of assembly.