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Fudgin [204]
3 years ago
10

Give reason 1)voltmeter is always connected in parallel 2)ammeter is always connected in series

Physics
1 answer:
77julia77 [94]3 years ago
8 0

Answer:

1)objects in parallel experience the same potential difference.Therefore the voltmeter is connected in parallel to the object for which we want to calculate the P.d

2}objects in series in a circuit experiance

the same current thus they have to be in series to have the same exact current

Explanation:

n\

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If you drop a bouncing ball from a height of 40 centimeters, explain why it can only bounce back up to a height of less than 40
iren2701 [21]

Answer:

Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height

Explanation:

As we know that initially ball is held at height h = 40 cm

So here we can say that kinetic energy of the ball is zero and potential energy is given as

U = mgH

now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies

So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height

While if we assume that there is no energy loss during collision then in that case ball will reach to same height again

8 0
3 years ago
A bus is designed to draw its power from a rotating flywheel that is brought up to 3000 rpm by an electric motor. The flywheel i
Arada [10]

To solve this problem we will apply the concept of rotational kinetic energy. Once this energy is found we will proceed to find the time from the definition of the power, which indicates the change of energy over time. Let's start with the kinetic energy of the rotating flywheel is

E_r = \frac{1}{2} I\omega^2

Here

I = moment of inertia

\omega = Angular velocity

Here we have that,

\omega = 3000\frac{rev}{min}(\frac{2\pi rad}{1rev})(\frac{1min}{60s})

\omega = 314.159rad/s

Replacing the value of the moment of inertia for this object we have,

E_r = \frac{1}{2} (\frac{MR^2}{2})\omega^2

E_r = \frac{1}{2} (\frac{2000(0.5)^2}{2})(314.159)^2

E_r = 1.233698*10^7J

The expression for average power is

P = \frac{E_r}{\Delta t}

\Delta t = \frac{E_r}{P}

\Delta t = \frac{1.233698*10^7}{20*10^3}

\Delta t = 616.8s \approx 620s

Therefore the correct answer is 620s.

3 0
4 years ago
If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface
Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile =\frac{1}{2}mv_e^2-\frac{GMm}{R}... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, v_e=\sqrt{\frac{2GM}{R}}

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} ...(2)

(1)=(2)

⇒\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}

⇒G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2

⇒\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})

⇒\frac{h}{R+h} = \frac{3}{4}

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.  

4 0
3 years ago
Read 2 more answers
The passenger-side rear view mirror on a car says, “Objects in the mirror may be closer than they appear”. Assuming the images a
Ipatiy [6.2K]

Answer:

the mirror is a convex mirror

4 0
3 years ago
The equation T squared = A cubed shows the relationship between a planet’s orbital period, T, and the planets mean distance from
Nataly [62]

Answer:

orbital period increased by a factor of 2.83 unit

Explanation:

Given.

planet’s orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU

T²= A³

If A is increased by a factor of 2 , .

Then T will be increase with the factor of √2³ = 2.83

3 0
3 years ago
Read 2 more answers
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