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Sedbober [7]
3 years ago
12

If you drop a bouncing ball from a height of 40 centimeters, explain why it can only bounce back up to a height of less than 40

centimeters.
Physics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height

Explanation:

As we know that initially ball is held at height h = 40 cm

So here we can say that kinetic energy of the ball is zero and potential energy is given as

U = mgH

now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies

So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height

While if we assume that there is no energy loss during collision then in that case ball will reach to same height again

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What are the five natural agents of erosion? What is the driving force behind all of these agents of erosion?
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Moving water, wind, gravity, and ice are the five natural agents of erosion
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A circuit consists of one 330 ohm resistor in series with two other resistors (470 ohms and 220 ohms) connected in parallel. Wha
umka21 [38]

Answer:

power drain on an ideal battery, P = 0.017 W

Given:

R_{1} = 330\ohm

R_{2} = 470\ohm

R_{3} = 220\ohm

Since, R_{2} = 470\ohm and R_{3} = 220\ohm are in parallel and this combination is in series with R_{1} = 330\ohm, so,

Equivalent resistance of the circuit is given by:

R_{eq} = \frac{R_{2}R_{3}}{R_{2} + R_{3}} + R_{1}

R_{eq} = \frac{470\times 220}{470 + 220} + 330

R_{eq} = 149.85 + 330 = 479.85 \ohm

power drain on an ideal battery, P = \frac{V^{2}}{R_{eq}}

                                                      P = \frac{2.9^{2}}{479.85}

                                                      P = 0.017 W

4 0
4 years ago
Which best describes the current atomic model?
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Hope this helps!</span>
3 0
3 years ago
Read 2 more answers
A terrorist throws a grenade with a 6.00 second fuse off a building 150.0 m high at a speed of 10.0 m/s. If the angle at which t
igomit [66]
Here we have a projectile motion. It is type of motion that is made of a vertical shot and a horizontal shot. This is how we will solve it.

Firste step is to find horizontal and vertical component of a speed.
v_{0x} =v_{0} * cos \alpha \\ v_{0y} = v_{0} * sin \alpha [/tex]

We are given this information:
v_{0} = 10 m/s \\ h=150m \\  \alpha =-30°
Angle is negative because it is below the horizontal.

VERTICAL SHOT
Time needed for a grenade to fall to the bottom of a building is given by a formula:
t= \frac{ v_{0y} }{g}  \\ t= \frac{v_{0} * sin \alpha}{g}  \\ t= \frac{-10*sin(-30)}{9.81} \\ t=0.51s
We used negative value for a speed because it is considered that upwards shot has positive value and downwards shot has negative value.

The grenade will not explode before it hits the ground.


HORIZONTAL SHOT
<span>The horizontal distance from the building at which the grenade will land is called range. The formula for a range is given by:
</span>R= v_{0x} * \sqrt{ \frac{2h}{g} } \\ R=v_{0} * cos \alpha* \sqrt{ \frac{2h}{g} } \\ R=10*cos(-30)* \sqrt{ \frac{2*150}{9.81} } \\ R=47.89m 

The grenade will hit the ground at distance of 47.89m.
7 0
3 years ago
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