If you drop a bouncing ball from a height of 40 centimeters, explain why it can only bounce back up to a height of less than 40
1 answer:
Answer:
Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height
Explanation:
As we know that initially ball is held at height h = 40 cm
So here we can say that kinetic energy of the ball is zero and potential energy is given as
now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies
So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height
While if we assume that there is no energy loss during collision then in that case ball will reach to same height again
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The radius of the cylinder is equal to half the diameter:
The volume of the cylinder is given by:
where h is the heigth of the cylinder. Converting into meters,
And the density of the material will be given by the ratio between the mass and the volume:
Answer:
10.55111 m/s²
Explanation:
M = Mass of Saturn =
r = Radius of Saturn =
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
Acceleration due to gravity is given by
The acceleration due to gravity on Saturn is 10.55111 m/s²
Answer:
d= 794.4 cmExplanation:
Given that
Speed ,V= 286 km/h
V=79.44 m/s
Given that time ,t= 100 ms
t= 0.1 s
We know that ( if acceleration is zero)
Distance = Speed x time
d= V t
Now by putting the values in the above equation
d = 79.44 x 0.1 m
d= 7.944 m
We know that 1 m = 100 cm
d= 794.4 cm