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Rama09 [41]
3 years ago
15

A 0.025m radius toy top is spinning at a rate of 150rpm, what is the angular velocity? What is the linear velocity of the paint

on the outside edge?
Physics
1 answer:
Sonja [21]3 years ago
8 0
A) The angular velocity of the disk is 150 rpm (revolutions per minute). We can convert it into proper units, i.e. radiants per seconds, keeping in mind that:
1 rev = 2 \pi rad
1 min = 60 s
so the angular speed is
\omega = 150  \frac{rev}{min}  = 150  \frac{2 \pi rad}{60 s} =15.7 rad /s

b) The linear velocity is given by
v=\omega r
since the radius is r=0.025 m, the linear velocity at the edge of the disk is
v= \omega r = (15.7 rad/s)(0.025 m)=0.39 m/s
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A particle is moving along a circular path of 2-m radius such that its position as a function of time is given by u = (5t 2) rad
OverLord2011 [107]

Answer:

Explanation:

Given

radius of  path r=2\ m

Velocity of Particle \theta =5t^2 rad

where t=time in seconds

angular velocity of particle is given by

\omega =\frac{\mathrm{d} \theta }{\mathrm{d} t}

\omega =2\times 5t=10\cdot t

And angular acceleration is given by

\alpha =\frac{\mathrm{d} \omega }{\mathrm{d} t}

\alpha =10 rad/s^2

tangential acceleration is a_t=\alpha \times r

a_t=10\times 2=20\ m/s^2

Centripetal acceleration a_c=\omega ^2\times r

a_c=(10t)^2\times 2=200t^2

net acceleration is sum of tangential and centripetal force at any time t is given by

a_{net}=\sqrt{(a_c)^2+(a_t)^2}

a_{net}=\sqrt{(200t)^2+(20)^2}

a_{net}=20\sqrt{(10t)^2+1}\ m/s

                 

8 0
3 years ago
John, paul, and george are standing in a strawberry field. paul is 14.0 m due west of john. george is 36.0 m from paul, in a dir
sdas [7]

Position of paul with respect to john is given as

14 m due west of john

r_{pj} = r_p - r_j = -14\hat i

position of George with respect to Paul is given as 36 m in direction 37 degree south of east

r_{GP} = r_G - r_p = 36cos37\hat i - 36 sin37\hat j

now we need to find the position of George with respect to John

r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j

r_{Gj} = 14.75\hat i - 21.67\hat j

so the magnitude is given as

r = \sqrt{14.75^2 + 21.67^2} = 26.2 m

and direction is given as

\theta = tan^{-1}\frac{21.67}{14.75}= 55.75 degree

<em>so it is 26.2 m at an angle 55.75 degree South of east</em>

7 0
3 years ago
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il63 [147K]

Answer:

82

Explanation:

According to law of reflection, the angle of incidence = angle of reflection

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3 years ago
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timofeeve [1]

Answer:

<u>because of the doppler effect</u>

Explanation:

<em>Remember</em>, the doppler effect refers to the changes in sound (frequency of sound) observed by a person who is in a position relative to the wave source.

In this example, we notice as the train comes closer to the boy, the sound becomes louder also increasing the pitch slightly, the doppler effect sets in when the train passes the boy because the boy notices a decrease in the pitch of the moving train.

We learn from the change in the observed sound of the train that the frequency of the sound is determined by the distance of the observer from the wave source.

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