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Lesechka [4]
3 years ago
11

Jennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month t

han the month before. She ended up saving $19,779.00. How much more did she save each month?
Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0
This is an arithmetic sequence with first term (a) = 11, number of terms (n) = 57, sum of nth term (Sn) = 19,779.
Let the amount of money she saved more each month be d, then
Sn = n/2(2a + (n - 1)d)
19,779 = 57/2(2(11) + (57 - 1)d)
19,779 = 28.5(22 + 56d)
19,779 = 627 + 1,596d
19,779 - 627 = 1,596d
d = 19,152/1,596 = 12

Therefore, she saved $12.00 more each month.
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Let's see where the angle is first:

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We can find the angle by using the inverse of the cosine:

\begin{gathered} \cos \theta=\frac{4}{5} \\ \cos ^{-1}(\frac{4}{5})=\theta \end{gathered}

But we have to be careful with this because the result will not be in the quadrant we want. The results of these operations are always in the first quadrant (between 0 and pi/2)

This one is:

\theta\approx0.6435\text{ rad}

To find the angle that is beween 3pi/2 and 2pi, we have to substract that angle from 2pi:

2\pi-0.6435\approx5.6397rad

And with that angle we can calculate the sine:

\sin (\theta)=-\frac{3}{5}

(I solved it with a calculator so I don't miss decimals and get a more exact answer)

The tangent is the quotient between the sine and the cosine:

\tan (\theta)=\frac{\sin\theta}{\cos\theta}=\frac{\frac{4}{5}}{-\frac{3}{5}}=-\frac{4\times5}{3\times5}=-\frac{4}{3}

7 0
1 year ago
Which is the recursive formula for finding the nth term in a geometric sequence?
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Let see how to build up this formula that is going to give that term of rank n

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4th a₄   = a₁  x  r³
5th a₅   = a₁  x  r⁴
.......................
.......................
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Note when that the subscript of a is the same as the exponent mines 1


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4 years ago
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Answer:

3.

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Step-by-step explanation:

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Alexis has $3.25 in nickels and dimes. The number of dimes is 5 less than twice the number of nickels. Find the number of nickel
jek_recluse [69]

Answer:

15 nickels were there with Alexis

Step-by-step explanation:

Let there be  x nickels

given that

The number of dimes is 5 less than twice the number of nickels.

no of dimes in terms of x = 2*number of nickels - 5 = 2x - 5

we know that

value of 1 nickel = 5 cents

then

value of x nickel = 5*x cents = 5x cents

we know that

value of 1 dime = 10 cents

then

value of 2x-5 dime = 10(2x - 5)  cents = 20x - 50 cents

Total value of x nickel and 2x -5 dimes = 5x + 20x - 50 = 25x - 50

given that

Alexia has total of  $3.25 in nickel and dimes thus  25x - 50 must be equal to $3.25

$1 = 100 cents

$3.25 = 3.25 * 100 cents = 325 cents

Thus,

25x - 50 = 325

25x = 325 + 50 = 375

x = 375/25 = 15

Thus, no of nickels = x = 15  answer

5 0
3 years ago
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