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3 years ago

Which of the following would be a solution to the system of inequalities below?

Mathematics

1 answer:

shutvik [7]3 years ago

7 0

I think it should be C

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the legs of a right triangle are 4 units and 7 units. What is the length of the hypotenuse? Select one: a. square root 33 units

Mrac [35]

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{4^2+7^2}\implies c=\sqrt{65}$

4 0

3 years ago

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6y + 4 – 3y = -5 + y + 17

Luda [366]

Answer:

Step-by-step explanation:

6y+4-3y=-5+y+17

6y-3y-y= -5+17-4

2y=8

y=4

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3 years ago

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Sandy baked 4 1/2 pounds of cookies. She divided the cookies equally among two friends and herself. How many cookies did each pe

suter [353]

Answer:

Each person would get 1 1/2 pounds worth of cookies

Step-by-step explanation:

4 1/2 pounds of cookies divided equally among 3 people

4 1/2 pounds divided by 3 people = 1 1/2 pounds of cookies

Each person gets 1 1/2 pounds of cookies

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3 years ago

What is the product of 2x + y and 5x – y + 3?

hoa [83]

Answer: The required product is $10x^2-y^2+3xy+6x+3y.$

Step-by-step explanation: We are to find the product f the following two algebraic expressions:

$E_1=2x+y,\\\\E_2=5x-y+3.$

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

$M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.$

Thus, the required product is $10x^2-y^2+3xy+6x+3y.$

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3 years ago

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Solve for u. 4u=10.24. Please answer thanks :)

ivolga24 [154]

Answer:

Simplifying

4u = 10.24

Solving

4u = 10.24

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Divide each side by '4'.

u = 2.56

Simplifying

u = 2.56

Step-by-step explanation:

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3 years ago

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