The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
Solution,
Let,(x1,y1)=(-4,-3)
(x2,y2)=(3,5)
Using distance formula,
AB=√(x2-x1)²+(y2-y1)²
=√(3+4)²+(5+3)²
=√49+64
=√113 units.
Step-by-step explanation:
Answer:
slope = 
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 6y - 14x = 5 into this form
add 14x to both sides
6y = 14x + 5 ( divide all terms by 6 )
y =
x +
← in slope- intercept form
with slope m =
← in simplest form
<span>Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at each point.
A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3.
</span>
Result:
(-7/4)x^2-13x
The roots are:
x= -52/7
x=0
See attached pictures.
2115000
x*10= 42300
x= 4230
x*500
4230*500= 2115000
Hope this helps