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2 years ago

5

Rashid has just purchased a health insurance policy that covers the cost of his preventive care. Which three of these expenses w

ould Rashid's
health Insurance cover?
regular screenings
telephone calls made for emergencies
regular health checkups
cost of traveling to the hospital
cost of Immunizations
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1 answer:

love history [14]2 years ago

5 0

Answer:

Regular screenings

Regular health checkups

Cost of immunizations

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you take out a mortgage for 350,000$ at 4% compounded monthly your payment is 1671$ write a recursive formula

Ymorist [56]

Answer:

Not sure if this is right but it might be something like

350,000-4%+1671m

or

3500,000-4%y/1671m

Step-by-step explanation:

The numbers we know are 350,000 4% and 1671 per month

350,000 is the full mortgage

4% is the APR or annual percentage rate like interest

and we know the monthly for the mortgage is 1671 per month

4 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

3 years ago

Math please help 10 points!

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

$average= \frac{sum of scores}{number of tests}$

$80= \frac{79+81+77+x}{4}$

80 x 4 = 79+81+77+x

320=237 + x

320-237 = x

83=x

so Marianne must score 83 points or higher on her last test

8 0

3 years ago

What is the solution set of (3x - 1)2 = 5?

Virty [35]

The answer to (3x-1)2=5 is x= 7/6

8 0

2 years ago

A winter jacket cost $200. It is on sale for 30% off when you have a coupon to save another 20%. How much do you have to pay for

Luba_88 [7]

Answer:

$100

Step-by-step explanation:

20%+30% = 50% off

50/100 = 1/2

200*1/2 = $100

5 0

2 years ago

Read 2 more answers