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siniylev [52]
2 years ago
5

5. How many ways are there to choose seven cards from a deck of 52?

Mathematics
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer:

674,274,182,400

Step-by-step explanation:

In this particular situation, the first card can be chosen in 52 ways. The second card can be chose in 51 (because when you chose the first card, there were 51 left), you keep doing that seven times

So, 52*51*50*49*48*47*46

Hope this helps.

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Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

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