The maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper is 512cm³.
<h3>How to calculate the volume?</h3>
From the information, when the side of 1cm are cut, this will become an open box. The volume will be:
= 18 × 18 × 1
= 324cm³
Also, when 2cm is cut, the volume will be:
= 16 × 16 × 2
= 512cm³
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5n + 4 = 39
5n = 39 -4
5n = 35
n = 35:5
n = 7
Answer:
5DG=156 I think this is but I am not sure bro
<u>Solution:</u> 48cm/s^2
<u>Working:</u>
A = s^2
Derivate s^2 (as it is area formula) which gives
dA/dt = 2s dL/dt
dL/dt = 6cm/s
Hence,
2(6) = 12
Side: 4cm
Hence,
dA/dt = (4)(12) = 48cm/s^2
<em>Feel free to mark this as brainliest :D</em>
Answer:
- height: 9 chi 6 cun
- width: 2 chi 8 cun
Step-by-step explanation:
The factor-of-ten relationship between the different units means we can combine the numbers in decimal fashion. If 1 unit is 1 zhang, then 1 chi is 0.1 zhang and 1 cun is 0.01 zhang. Hence 6 chi 8 cun is 0.68 zhang.
Let x and y represent the width and height, respectively. In terms of zhang, we have ...
y - x = 0.68
x^2 +y^2 = 1^2
Substituting y = 0.68 +x into the second equation gives ...
x^2 + (x +0.68)^2 = 1
2x^2 +1.36x - 0.5376 = 0 . . . . . eliminate parentheses, subtract 1
Using the quadratic formula, we have ...
x = (-1.36 ±√(1.36^2 -4(2)(-0.5376)))/(2·2) = (-1.36 ±√6.1504)/4
x = 0.28 . . . . . the negative root is of no interest
y = 0.28 +0.68 = 0.96
In units of chi and cun, the dimensions are ...
height: 9 chi 6 cun
width: 2 chi 8 cun
