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givi [52]
3 years ago
8

Write the rule for this sequence '32,16,8,4'

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Step-by-step explanation:

This is a sequence of divide by 2 or half of the number so 32 16 8 4 2 1

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Explain how a number line can be used to find the difference for 34-28
slega [8]
For example, if the number line is like this,
---------28-29-30-31-32-33-34-35
You find 34 on the number line, then count down to 28-which is 6, so 34-28=6
7 0
4 years ago
Write a rule for the linear function in the graph<br> Plz help
Scilla [17]

Answer:

  y = -x +4

Step-by-step explanation:

The y-intercept of the line is at +4, so the only viable choice is the last choice.

___

Each of the equations is shown in slope-intercept form:

  y = mx + b

where b is the y-intercept, the y-value when x=0. The graph shows that as point (0, 4). So, the equation you're looking for is ...

  y = (some x-term) +4

If you want to spend more brain power on the problem, you can compute the slope of the line as ...

  m = ∆y/∆x = (1-4)/(3-0) = -3/3 = -1

Now, you know for sure the equation of the line is ...

  y = -x +4

4 0
4 years ago
Write an irrational number that can be added to the irrational number √28 to get a rational sum of 8.
tamaranim1 [39]

Answer: 2.82

Step-by-step explanation:

7 0
3 years ago
Solve for x because it was too hard to me
Yuri [45]
This is tricky
lets try  substituting  y = √)6x - 9)

√(6 - y) + √(6x + y) = √6

squaring both sides:-

6 - y + 6 + y - 2√(6 - y)(6 + y) = 6
12 - 2√(6 - y)(6 + y) = 6
√(6 - y)(6 + y) = (6-12) / -2 = 3
Squaring both sides:-
(6 - y)(6 + y) = 9
36 - y^2 = 9
y^2 = 27
y = +/-√27

√(6x - 9) = +/- 27

6x - 9 = 729

x = 738/6  =  123

This cannot be a solution because   we would have a negative value for the 
second square root

I would say that no solution exist.


8 0
3 years ago
Using inductive reasoning, what are the next three numbers in the sequence 3,6,12,24?
igor_vitrenko [27]

Step-by-step explanation:

the answer is 1 because every time the number doubles

3 0
3 years ago
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