After the donation,
3m + m = 132
manual = 33
digital = 99
Before the donation, he had 82 more digital and 26 more manual cameras.
82 + 99 = 181 digital
26 + 33 = 59 manual
For a double check, before donation,
digital + manual = 240
181 + 59 = 240
So, to begin with, the number of digital cameras = 181.
Answer:
131.3 miles
Step-by-step explanation:
The two cars are moving from different directions. The total distance between the two cars = 118 miles + 256 miles = 374 miles.
Let us assume that the two cars meet at point O, let the distance between car c and O be d₁, the distance between car d and point O be d₂, hence:
d₁ + d₂ = 374 miles (1)
Let speed of car d be x mph, therefore speed of car c = 2x mph (twice of car d). If it take the cars t hours to meet at the same point, hence
For car c:
2x = d₁/t
t = d₁ / 2x
For car d;
x = d₂/t
t = d₂/ x
Since it takes both cars the same time to meet at the same point, therefore:
d₁/2x = d₂ / x
d₁ = 2d₂
d₁ - 2d₂ = 0 (2)
Solving equation 1 and 2 simultaneously gives d₁ = 249.3 miles, d₂ = 124.7 miles
Therefore the distance from point of meet to Boston = 249.3 - 118 = 131.3 miles
Answer:
5 or 6 (or 2 or 7)
Step-by-step explanation:
Any quadrilateral can be covered by 2 triangles, so the integer number in 7/3 = 2 1/3 quadrilaerals will require 2×2 = 4 triangles.
The meaning of (1/3) trapezoid determines the number of additional triangles required. If 1/3 trapezoid is a triangle, only one is needed. If 1/3 trapezoid is a quadrilateral, then 2 triangles are needed.
_____
If the 7/3 trapezoids are butted against each other so they make a larger quadrilateral figure, then only 2 triangles are needed.
_____
If each trapezoid is constructed from 3 equilateral triangles, and you want to know the total number of those equilateral triangles in 7/3 such figures, it will be 3 × 7/3 = 7.
The answer depends on problem details not provided here.
Answer:
sinB= 3/5, tanA=4/3, cosB=4/5
Step-by-step explanation:
