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Nina [5.8K]
3 years ago
14

Molar mass in silver nitrate

Chemistry
2 answers:
ohaa [14]3 years ago
7 0

Answer:169.87 g/mol

Explanation: (107.87 +14.007 + (3 x 15.999))= 169.874

lesya692 [45]3 years ago
4 0

Answer:

169.87 grams

Explanation:

The formula for silver nitrate is AgNO3.

To find the molar mass, find the mass of each individual element in the compound.

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Can y’all help me with this question How many atoms are found in the chemical formula below Al2( SiO3)2
Arte-miy333 [17]

Answer:

the answer is 10

Explanation:

Al2 is 2 atoms by itself

(SiO3)2 is 8 because Si is a single atom and O3 is 3 oxygen atoms but because of the subscript outside of the parentheses it doubles and becomes 2 and 6 respectively

7 0
3 years ago
A reaction produces 0.829 moles of H2O. How many molecules are produced?
mr_godi [17]
You should get 5.05 x 10^23 moles.
8 0
4 years ago
What is the temperature of a 6.1 mole sample of He gas at 18.5 bar and volume of 115L? (Round answer to the hundredths place)
Bond [772]

Answer:

4202.1 K

Explanation:

From;

PV=nRT

P= pressure of the gas = 18.5 bar

V = volume of the gas = 115L

n= number of moles of the gas =  6.1 mole

T= temperature of the gas = ?

R = gas constant = 0.083 L⋅bar⋅K−1⋅mol−1

T = PV/nR

T = 18.5 * 115/6.1 * 0.083

T = 2127.5/0.5063

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7 0
3 years ago
Luis set a glass of ice water out side is the sunshine . when he looked at the glass 10 minutes later, the contents had changed.
abruzzese [7]

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8 0
3 years ago
Read 2 more answers
A 11.79 g sample of Mo2O3(s) is converted completely to another molybdenum oxide by adding oxygen. The new oxide has a mass of 1
Elis [28]

Answer:

MoO₃

Explanation:

To solve this question we must find the moles of molybdenum in Mo2O3. The moles of Mo remain constant in the new oxide. With the differences in masses we can find the mass of oxygen and its moles obtaining the empirical formula as follows:

<em>Moles Mo2O3 -Molar mass: 239,878g/mol-</em>

11.79g * (1mol / 239.878g) = 0.04915 moles Mo2O3 * (2mol Mo / 1mol Mo2O3) = 0.09830 moles Mo

<em>Mass Mo in the oxides:</em>

0.09830 moles Mo * (95.95g/mol) = 9.432g Mo

<em>Mass oxygen in the new oxide:</em>

14.151g - 9.432g = 4.719g oxygen

<em>Moles Oxygen:</em>

4.719g oxygen * (1mol/16g) = 0.2949 moles O

The ratio of moles of O/Mo:

0.2949molO / 0.09830mol Mo = 3

That means there are 3 moles of oxygen per mole of Molybdenum and the empirical formula is:

<h3>MoO₃</h3>
3 0
3 years ago
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