Answer:
32.5g of sodium carbonate
Explanation:
Reaction of sodium carbonate (Na₂CO₃) with Mg²⁺ and Ca²⁺ as follows:
Na₂CO₃(aq) + Ca²⁺(aq) → CaCO₃(s)
Na₂CO₃(aq) + Mg²⁺(aq) → MgCO₃(s)
<em>1 mole of carbonate reacts per mole of the cations.</em>
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To know the mass of sodium carbonate we must know the moles of carbonate we need to add based on the moles of the cations:
<em>Moles Mg²⁺:</em>
2.91L * (0.0661 moles MgCl₂ / 1L) = 0.192 moles MgCl₂ = Moles Mg²⁺
<em>Moles Ca²⁺:</em>
2.91L * (0.0396mol Ca(NO₃)₂ / 1L) = 0.115 moles Ca(NO₃)₂ = Moles Ca²⁺
That means moles of sodium carbonate you must add are:
0.192 moles + 0.115 moles = 0.307 moles sodium carbonate.
In grams (Using molar mass Na₂CO₃ = 105.99g/mol):
0.307 moles Na₂CO₃ * (105.99g / mol) =
<h3>32.5g of sodium carbonate</h3>
1. Answer:
B) An allele is one form of a gene.
Explanation:
- <em><u>An allele refers to an alternative form of a gene. In other words it is one of the form of a gene.</u></em>
- <em><u>A gene may have two alleles, where one of the allele is a dominant allele and the other is a recessive allele. </u></em>
- A homozygous organisms may be dominant or recessive, a homozygous recessive contains two recessive alleles while a homozygous dominant contains two dominant alleles.
- A heterozygous organisms contain one dominant allele and one recessive allele.
2. Answer;
B) Alleles
Explanation;
- <em><u>According to Mendel genes are inherited in pairs of alleles that behave in a dominant and recessive pattern. </u></em>
- <em><u>Alleles are alternative forms of a gene. </u></em>
- A gene may have two alleles, where one of the allele is a dominant allele and the other is a recessive allele.
- A homozygous organisms may be dominant or recessive, a homozygous recessive contains two recessive alleles while a homozygous dominant contains two dominant alleles.
Answer: The molecular weight of the gas 28. The gas is probably N2
Explanation:Please see attachment for explanation
Its obviously D like what are you stupid lol jk don’t take it to heart kid
Answer:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)
Explanation:
Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:
- an equilibrium constant is, first of all, a fraction;
- in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
- in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
- each concentration should be raised to the power of the coefficient in the balanced chemical equation;
- only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.
Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:
