How many atoms are in 3.5 moles of arsenic atoms?

Chemistry

1 answer:

goblinko [34]2 years ago

3 0

Answer:

1 mol of atoms = 6.022 ×1023 atoms. 3.5mol × 6.022 × 1023 atoms 1mol = 2.11 × 1024 atoms =.........

Explanation:

2160.64 atoms!

You might be interested in

The molar madd of Ca(OH)2

Nonamiya [84]

What you have to do is find a periodic table and add the mass of each atom that the compound is made of.

Ca= 40.1
O= 16.0
H= 1.01

keep in mind that you have to also account for how many atoms of each there are in the molecule. for example, in Ca(OH)2, there are one Ca, two O and two H

so the molar mass of Ca(OH)2= 40.1 + (2 x 16.0) + (2 x 1.01)= 74.12 g/mol

8 0

3 years ago

.) What happens when Carbon dioxide gas is Collected down ward of water ?

Free_Kalibri [48]

when carbon dioxide gas is collected down ward of water wet gas is collected by the downward displacement of water . This is used for gases that are not very soluble in water . ... In water , carbon dioxide produces a weakly acidic solution , carbonic acid .

8 0

3 years ago

Who goes to K12 and if so what grade

olchik [2.2K]

Answer:

I might next year with my cuz and nex year ima be in 8th

Explanation:

8 0

3 years ago

Read 2 more answers

Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L

8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is $P_A$ and vapour pressure of component B is $P_B$ .

$P^0_A$ = Vapour pressure of component A in pure form

$P^0_B$ = Vapour pressure of component B in pure form

$x_A$ =Mole fraction of component A

$x_B=$ =Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

$P_A >P^0_A\cdot x_A$ , $P_B>P^0_B\cdot x_B$