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USPshnik [31]
2 years ago
5

Happy Earth Day. Have a wonderful Day! If you answer you must give me ten Earth day Activities to answer. Thank you!

Mathematics
2 answers:
Gelneren [198K]2 years ago
8 0

Answer:

  • Build a Container Fairy Garden
  • Make a Play Garden, a carved out space just for the kids to dig and plant in.
  • Pinecone and Peanut Butter Bird Feeder
  • Get out the acrylic paint and make some Painted Sticks
  • Leaf Necklaces
  • On your next beach trip, collect some Shells and paint them
  • Grow Wheat Grass Indoors {the fastest growing plant}
  • Make some beautiful Nature Prints made with Sculpey
  • Make leaf sun prints on fabric
  • These Fabric Sunprints is the ultimate of earth day activities since it’s a science experiment and art project wrapped up in one.
  • \infty  \infty
emmasim [6.3K]2 years ago
5 0

Answer:

Happy Earth Day to u too.

Step-by-step explanation:

1) Plant a sapling

2) Draw a poster related to Earth Day

3) Color a picture of the Earth/ tree

4) Decorate ur room with plants

5) Prepare a speech on Earth Day

6) Do T-shirt designing with Earth as a design

7) Buy a paper/ cloth bag

8) Recycle what u use

9 Avoid plastic

10) Use bikes or walk instead of vehicles

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Find the mean of 100​
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Answer:

100.

Step-by-step explanation:

100 + 0 = 100

100 ÷ 1 = 100

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This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

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Which of the following statements about feasible solutions to a linear programming problem is true?A. Min 4x + 3y + (2/3)z
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Answer:

The answer is "Option A"

Step-by-step explanation:

The valid linear programming language equation can be defined as follows:

Equation:

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The description of a linear equation can be defined as follows:

It is an algebraic expression whereby each term contains a single exponent, and a single direction consists in the linear interpolation of the equation.

Formula:

\to \boxed{y= mx+c}

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