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Eddi Din [679]
2 years ago
13

Please help!!

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
8 0

Answer:  Check out the screenshot below for the answers

==========================================================

Explanation:

For each column, we divide the values by the sum of each column.

The sum of the first column is 6+8 = 14, and the sum of the second column is 7+3 = 10.

Column 1:

  • 6/14 = 0.43
  • 8/14 = 0.57

Those values are approximate to two decimal places.

Column 2:

  • 7/10 = 0.70
  • 3/10 = 0.30

Those values are exact.

The values in bold are then filled in the table as you see below.

A result like 0.43 means that 43% of those who play a sport also play an instrument. The other values are interpreted in a similar fashion.

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First step would be to figure out how many litres we have, which is 5.

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4 0
3 years ago
Read 2 more answers
An experiment consists of choosing an urn with the following probabilities that Urn 1, Urn 2, or Urn 3 will be chosen: 1/2, 1/4,
Alborosie

Answer:

option E

Step-by-step explanation:

let E₁ be the event of urn 1

let E₂ be the event of urn 2

let E₃ be the event of urn 3

P(E₁) = \dfrac{1}{2}

P(E₂) = \dfrac{1}{4}

P(E₃) = \dfrac{1}{4}

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P(A/E₁) = \dfrac{14}{29} =0.483

P(A/E₂) = \dfrac{11}{26} = 0.423

P(A/E₃) = \dfrac{8}{20} =  0.4

required probability

P(E₃/A) = \dfrac{P(E_3)P(A/E_3)}{P(A)}

P(A) = P(E₁)P(A/E₁) + P(E₂)P(A/E₂) +P(E₃)P(A/E₃)

P(A) = 0.5 x 0.483  + 0.25 x 0.423 +0.25 x 0.4

P(A) = 0.447

now,

P(E₃/A) = \dfrac{0.25 \times 0.4}{0.447}

P(E₃/A) = 0.2147

hence, the correct answer is option E

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Answer:

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