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3 years ago

If the root of x2-7x+k=0, m=1, find the value of the constant k

Mathematics

1 answer:

Whitepunk [10]3 years ago

4 0

Answer:

hfrhghubifhvfuovhtjopugjob

Step-by-step explanation:

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A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re

Daniel [21]

From the equation of motion, we know,

$s=ut+\frac{1}{2}at^{2}$

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.

A = $-9.8m/s^{2}$ since the ball is thrown upwards.

Plug the known values into the equation.

=> $0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})$

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top = $\frac{3.4}{2} = 1.7 sec$

$v^{2}=u^{2}+2as$

=> $0=(16.67)^{2}+2(-9.81)(s)$

Solving for s we get

s= 14.16 m

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3 years ago

An uber in Los Angeles charges $3.50 per mile and $2 for every person. If taxi cab ride for three people costs $20, how far did

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victus00 [196]

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3 years ago

Find the area of the figure below

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2 years ago

Solve quadratic formulax^2-4x+3=0

bekas [8.4K]

The general formula for a equation of the form:

$ax^2+bx+c=0$

is:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

$\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}$

then:

$x_1=\frac{4+2}{2}=\frac{6}{2}=3$

and

$x_2=\frac{4-2}{2}=\frac{2}{2}=1$

Therefore, x=3 or x=1.

8 0

7 months ago