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kicyunya [14]
3 years ago
8

Prove that \P(A) \cup \P(B) \subseteq \P(A \cup B) and find a counter-example to show that we don't always have equality

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when X ∈ P ( A U B )

Step-by-step explanation:

To  Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well

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EleoNora [17]
The answer for the question is -5r+5
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3 years ago
The pipe has a length 29cm, internal diameter 6.5cm and thickness 0.5cm. What is the Volume
Reptile [31]

Answer:

Length of pipe = 21 cm

Internal diameter = 4 cm

Internal radius = \frac{4}{2} = 2 cm24=2cm

Thickness = 0.5 cm

Outer radius = 2+0.5=2.5 cm

Volume of pipe =\pi R^2 h - \pi r^2 hπR2h−πr2h

Volume of pipe =\frac{22}{7} (2.5)^2 (21)-\frac{22}{7}(2)^2(21)=148.5 cm^3

=\frac{22}{7} (2.5)^2 (21)-\frac{22}{7}(2)^2(21)=148.5 cm^3722(2.5)2(21)−722(2)2(21)=148.5cm3

Hence The volume is 148.5 cubic cm.

#more

The thickness of a metal pipe is 1.5cm. The inner diameter is 21cm. What is the volume of metal required for a pipe of length 7cm

5 0
2 years ago
Ln (x-2) +ln (2x-3)=2ln x
goblinko [34]
D:x-2\ \textgreater \ 0 \wedge 2x-3\ \textgreater \ 0 \wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2 \wedge x\ \textgreater \ \dfrac{3}{2}\wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2\\\\
\ln (x-2) +\ln (2x-3)=2\ln x \\
\ln (x-2)(2x-3)=\ln x^2\\
(x-2)(2x-3)=x^2\\
2x^2-3x-4x+6=x^2\\
x^2-7x+6=0\\
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4 0
3 years ago
Complete the ordered pairs so that they are solutions of the linear equation 5x + y = -21: (-6, ___), (0, ___), (1, ___).
Iteru [2.4K]
<span>5x + y = -21:
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5 0
3 years ago
Read 2 more answers
Bailey buys a car for $18,000 and it has a depreciation value of 16% per year after 3
sergiy2304 [10]

Answer:

$10668.67

Step-by-step explanation:

If the car value goes down 16% each year, after the first year, it will be worth 1520.

The next year, it will be worth $12700.80

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2 years ago
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