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kicyunya [14]
3 years ago
8

Prove that \P(A) \cup \P(B) \subseteq \P(A \cup B) and find a counter-example to show that we don't always have equality

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when X ∈ P ( A U B )

Step-by-step explanation:

To  Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well

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