2 years ago

Prove that \P(A) \cup \P(B) \subseteq \P(A \cup B) and find a counter-example to show that we don't always have equality

Mathematics

1 answer:

pentagon [3]2 years ago

3 0

Answer:

P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when $X$ ∈ P ( A U B )

Step-by-step explanation:

To Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well

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2 years ago

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goldenfox [79]

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