Answer:
P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when ∈ P ( A U B )
Step-by-step explanation:
To Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well
6
3 ⋅ 2^t
Let t=1
3 ⋅ 2^1
Exponents first
3 * 2
Substitute n = 12:
x=47is your answer
3x-11=130(alternate angle)
3x=130+11
x=141/3=47