Answer:
P(A) ∪ P(B) ⊆ P(A ∪ B) can be proved when ∈ P ( A U B )
Step-by-step explanation:
To Prove that P(A) ∪ P(B) ⊆ P(A ∪ B) is attached below and also a counter example to prove that we do not always get an equality is attached below as well
20b+8h=20
40
b² - 4ac
= 16 - 4(3)(-2)
= 16 + 24
= 40
Answer:$164.35
You just multiply 19 × 8.65
Answer: b= -108
-6=b/18
-6=b/2(3)^2
-18(6)=b
-108=b
b= -108
*<u><em>I hope that this makes sense :)</em></u>