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kaheart [24]
2 years ago
13

Pls help me with this ​

Mathematics
1 answer:
Musya8 [376]2 years ago
4 0
<h3>Adjacent is not acute or right angle. Right angles are 90 degrees and acute are 89 and below. </h3><h3 /><h3>Adjacent are 91 and above so  ACD would be adjacent and so would PRS.</h3><h3></h3><h2>Anwsers are: <em><u>ACD & PRS</u></em></h2><h2></h2><h2></h2>
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1.2 x 10^19 x 5.88 x 10^12
Lapatulllka [165]

9514 1404 393

Answer:

  7.056 × 10^31

Step-by-step explanation:

The applicable rule of exponents is ...

  (10^a)(10^b) = 10^(a+b)

__

  (1.2\times10^{19})\times(5.88\times10^{12})=(1.2\cdot5.88)\times10^{19+12}\\\\=\boxed{7.056\times10^{31}}

As you know, the commutative and associative properties of multiplication let you rearrange the order of the product to any convenient form. Here it is convenient to group the mantissas together and the powers of 10 together.

__

<em>Additional comments</em>

This is a product your scientific or graphing calculator can produce for you. Likely it will display the result in scientific notation because it won't have enough display digits to show you the product any other way. For smaller numbers, you can set the display mode to give you scientific notation.

If you choose to use a spreadsheet to perform this calculation, the numbers would be entered as 1.2e19 and 5.88e12. The result will be something like 7.056e31. You may have to format the display to show 3 decimal places.

7 0
2 years ago
In winter, the price of apples suddenly went up by $ 0 . 7 5 $0.75dollar sign, 0, point, 75 per pound. Sam bought 3 33 pounds of
elena-s [515]
Your answer ,It would be 24,925
6 0
2 years ago
How do you construct a frequency distribution table using sturge’s approximation
artcher [175]

The steps to use to construct a frequency distribution table using sturge’s approximation is as below.

<h3>How to construct a frequency distribution table?</h3>

The steps to construct a frequency distribution table using Sturge's approximation are as follows;

Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.

Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;

K = 1 + 3.322logN

where;

K= Number of classes

logN = Logarithm of the total number of observations.

Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size

Step 4; Locate the starting point: The lower class limit should take care of the smallest value in the raw data.

Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.

Step 6; Distribute the data into respective classes:

Read more about  frequency distribution table at; brainly.com/question/27820465

#SPJ1

6 0
2 years ago
At a football stadium, 5% of the fans in attendance were teenagers. If there were 10 teenagers at the football stadium, what was
TiliK225 [7]

Answer:

200 people were at the stadium

Step-by-step explanation:

Let us represent the total number of people at the stadium = x

At a football stadium, 5% of the fans in attendance were teenagers. If there were 10 teenagers at the football stadium

Hence:

5% of total number of people = 10 teenagers

5/100 × x = 10

5x/100 = 10

Cross Multiply

5x = 100 × 10

5x = 1000

Divide both sides by 5

5x/5 = 1000/5

x = 200

The total number of people in the stadium is 200

6 0
3 years ago
At what point of the curve y = cosh(x does the tangent have slope 2?
Dahasolnce [82]
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
5 0
2 years ago
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