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AnnZ [28]
3 years ago
5

Find Horizontal and Vertical Asymptotes for y=(1)/((x+2)^3)

Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0

Answer:

Vertical asymptote: x = -2

Horizontal asymptote: y = 0 or x axis.

Step-by-step explanation:

The rational function is given as:

y=\frac{1}{(x+2)^3}

Vertical asymptotes are those values of x for which the function is undefined or the graph moves towards infinity.

For a rational function, the vertical asymptotes can be determined by equating the denominator equal to zero and finding the values of x.

Here, the denominator is (x+2)^3

Setting the denominator equal to zero, we get

(x+2)^3=0\\(x+2)=0\\x=-2

Therefore, the vertical asymptote occur at x=-2.

Horizontal asymptotes are the horizontal lines when x tends towards infinity.

For a rational function, if the degree of numerator is less than that of the denominator, then the horizontal asymptote is given as y=0.

Here, there is no x term in the numerator. So, degree is 0. The degree of the denominator is 3. So, the degree of numerator is less than that of denominator.

Therefore, the horizontal asymptote is at y=0 or x axis.

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What is the slope of the line that passes through the points (5,7) and (-1, 19) ?
Alexandra [31]

For this case we have that by definition, having two points through which a line passes (x_ {1}, y_ {1})\ and\ (x_ {2}, y_ {2}), we can find its slope of the following form:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

If we have:

(x_ {1}, y_ {1}) = (5,7)\\(x_ {2}, y_ {2}) = (- 1,19)\\m = \frac {19-7} {- 1-5}

We know that equal signs are added and the same sign is placed

m = \frac {12} {- 6}\\m = -2

So, the slope of that line is m = -2

Answer:

m = -2


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3 years ago
8x-4[2x-5(3x+1)]-2[x-(x-1)] I hate math
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Answer:

60x + 18

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Step-by-step explanation:

The large ones cost $4 more so what you would do is to subtract that $4 from the $24.

24-4=20

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Step-by-step explanation:

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