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Tema [17]
3 years ago
8

Two students are standing 20ft apart and spot Mrs. Rose. If they immediately run opposite directions with speeds of 300ft/min an

d 200ft/min, how many minutes will pass until they are 3,000ft apart?
Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

They would be separating at 500 ft/min

time to go 3000 ft at that speed

= 3000/500 min

or

= 6 minutes

this may help you

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Answer:

\textbf{y = 9x + 21 }\\

Step-by-step explanation:

\textup{Given equation is: $4x + 36y = 80  $}\\\textup{This can be written in the form of $y = mx + a$ as follows}\\$ 36y = -4x + 80 $\\$ \implies y = \frac{80}{36} - \frac{4}{36}x $\\$ \implies y = \frac{-1}{9}x + \frac{20}{9} $\\\textup{This means that the slope of this line is $m = \frac{-1}{9}$}\\

\textup{Then the slope of the line perpendicular to this line would be \textbf{negative reciprocal of m}.}\\$i.e.,$ \textup{Slope of the perpendicular line would be $m_1 = \frac{-1}{\frac{-1}{9}}$}\\$\implies m_1 = 9$\\

\textup{The perpendicular line passes through the point $(3,6)$}\\\textup{Using the \textbf{point-slope formula}, we get:}\\

$$ y - y_1 = m(x - x_1) $$$ \implies y - 6 = 9(x - 3) $\\\textup{After solving this reduces to $y = 9x + 21$ }

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Step-by-step explanation:

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