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2 years ago

Can you please help me answer this?

Mathematics

2 answers:

In-s [12.5K]2 years ago

8 0

Lelelelelelelelell sry

neonofarm [45]2 years ago

4 0

The answer would be 34 acres

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the owner of an aquatic store used 17 1/2 gallons of water to fill aquariums. he puts 5 5/6 gallons of water in each aquarium. h

BabaBlast [244]

I have absolutely no idea. sorry that i didn’t answer but thanks for the second answer that i needed to ask my question. i’m stupid do i have no idea what it’s asking. sorry

6 0

3 years ago

Of the 725 students at Franklin Middle School, 12/25 play a sport. How many students play a sport at Franklin Middle School?

Paladinen [302]

Answer:

348 out of 725

Step-by-step explanation:

This is a ratio question, giving us a sample that we can use to extend the number to all students.

12/25 students play a sport so we want the value of x in x/725

So:

12/25 = x/725

Cross-Multiply:

25x = 8700

Divide by 25 to get x:

348

You can also check by dividing these ratios to see if you get the same number. In this case, you do (.48).

8 0

3 years ago

Ivan evaluated the expression 8+12÷3×2 and got 10. What mistake did he make?

lesya [120]

Ivan forgot to follow PEMDAS
Division first
12/3 = 4
4 x 2 = 8
8 + 8 = 16
Hope this helps!

3 0

2 years ago

Read 2 more answers

Please help, thanks!

garri49 [273]

Answer:

Step-by-step explanation:

That is the correct answer

that is correct

8 0

3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

2 years ago

Read 2 more answers