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wolverine [178]
3 years ago
11

The admission fee at a carnival fair is $4.50 for children

Mathematics
2 answers:
ycow [4]3 years ago
8 0
1386 for adults and 814 for children
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

Adult=1,385.71

Children=814.29

Approximately

Adult=1386

Children=814

Step-by-step explanation:

c= number of children

a= number of adults

Admission fee for children=$4.50

Admission fee for adults=$8.00

Total attendees=2200

Total amount realized=$5050

We need two equations to solve the two unknowns

c + a=2200 (1)

4.50c + 8.00a=5,050 (2)

From (1)

c + a=2200

c=2200 - a

Substitute c=2200 - a into (2)

4.50c + 8.00a=5,050

4.50(2200 - a) + 8.00a=5050

9900 - 4.50a +8.00a=5050

Collect like terms

9900-5050= -4.50a+8.00a

4,850=3.5a

Divide both sides by 3.5

1,385.71=a

Substitute a=1,385,71 into (1)

c + a=2200

c+1385.71=2200

c=2200-1385.71

=814.29

c=814.29

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Read 2 more answers
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

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