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Ilia_Sergeevich [38]
2 years ago
7

22. A figure is shown.

Mathematics
1 answer:
Feliz [49]2 years ago
7 0

Answer: 9.04

Step-by-step explanation:

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Answer: sin 33° and cos 57°

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Solve the inequality.    <br>       3m ≤ –9<br> A.m ≥ –3<br> B.m ≤ –3 <br> C.m ≥ 6  <br> D.m ≤ –6
marin [14]
3m \leq -9\ /:3 \ \ \ \Rightarrow\ \ \ m \leq -3\ \ \ \Rightarrow\ \ \ Ans.\ B
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3 years ago
Point P'P
Snowcat [4.5K]

<u>Given</u>:

The point P' is the image of the point P under the translation (x,y) \implies (x-6, y-1)

The coordinates of the point P are (6,0)

We need to determine the coordinates of the point P'

<u>Coordinates of the point P':</u>

The coordinates of the point P' can be determined by substituting the coordinates of the point P(6,0) in the translation.

Thus, substituting the coordinates, we have;

(6,0)\implies (6-6,0-1)

Simplifying the coordinates, we get;

(6,0)\implies (0,-1)

Thus, the coordinates of the point P' is (0,-1)

5 0
3 years ago
Draw two polygons that have corresponding angles that are all congruent but are not similar to prove that angle congruence is no
Marina86 [1]

There are infinitely many ways to do this. One such way is to draw a very thin stretched out rectangle (say one that is very tall) and a square. Example: the rectangle is 100 by 2, while the square is 4 by 4.

Both the rectangle and the square have the same corresponding angle measures. All angles are 90 degrees.

However, the figures are not similar. You cannot scale the rectangle to have it line up with the square. The proportions of the sides do not lead to the same ratio

100/4 = 25

2/4 = 0.5

so 100/4 = 2/4 is not a true equation. This numerically proves the figures are not similar.

side note: if you are working with triangles, then all you need are two pairs of congruent corresponding angles. If you have more than three sides for the polygon, then you'll need to confirm the sides are in proportion along with the angles being congruent as well.

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3 years ago
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