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2 years ago

22. A figure is shown.

Mathematics

1 answer:

Feliz [49]2 years ago

7 0

Answer: 9.04

Step-by-step explanation:

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F(x)=(x-2)2 X=8 Need answers ASAP

Zina [86]

Answer:

substitute 8 into x =(8-2)2

(6)2=12

4 0

3 years ago

Can someone help solve this

sdas [7]

The lnl is an absolute number which basically means it's positive regardless
So now its 7n-7=14
Simply add the 7 to the 14 to get it off the 7n side so you can simplify
Now it's 7n=21
Now just divide
21/7=3
3=N
That means 7 times N=21

8 0

2 years ago

What is an equation of the line that passes through the points (-6, -2) and

den301095 [7]

Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

6 0

2 years ago

What is the product?

Tanzania [10]

Answer:

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

Step-by-step explanation:

$\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}$

Multiply the row of the first matrix to the column of the second matrix

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1$

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\$

$=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}$

simplifying them we get

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

8 0

2 years ago

A commercial builder has a downtown lot with 250 frontage feet on Broadway. The lot is 200’ deep. By code, the builder must allo

Morgarella [4.7K]

Subtract 15 from the depth:

200-15 = 185

Subtract 20 from the width ( 10 from both sides)

250-20 = 230

Area to build on: 185 x 230 = 42,550 square feet.

8 0

3 years ago