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marysya [2.9K]
3 years ago
11

Please help me on a timer ✨

Mathematics
1 answer:
mestny [16]3 years ago
7 0

To find the area of the full shape, we can find the areas of individual smaller shapes and add them together. Lets break this up into a rectangle and a triangle.


The rectangle is easy to calculate as we already have its measurements. The area of a rectangle is h*w=A.

25*36=A

900=A


Next the triangle, and we need to do some logic work with the measurements to find the necessary measurements to take the area.


We know the base of the triangle is some part of 36 feet. We also know from the image that the part of the 36 that is not part of the base of the triangle is 12. Therefore, the base of the triangle is 36 - 12 = 24.


Now we need the height of the triangle. We know the height of the triangle is some part of 39, and the part that is not part of the triangle is 25. Therefore, the height of the triangle is 39 - 25 = 14.


We now have the height and base of the triangle and can find its area. The area of a triangle is 0.5wh=A.

0.5(24)(14)=A

168=A


Finally, we just need to add the two results together to find the total area.

168 + 900 = A

1068 = A


The total area of the shape is 1068.

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The place with the best buy between village market and Sam's club is Sam's club at $0.59 per can.

<h3>Unit rate</h3>

Village market:

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Unit rate = Total cost / green beans

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Unit rate = Total cost / green beans

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Therefore, the place with the best buy between village market and Sam's club is Sam's club at $0.59 per can.

Learn more about unit rate:

brainly.com/question/4895463

#SPJ1

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Refer to the photo :D
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well, we know the ceiling is 6+2/3 high, and Eduardo has 4+1/2 yards only, how much more does he need, well, is simply their difference, let's firstly convert the mixed fractions to improper fractions and then subtract.

\stackrel{mixed}{6\frac{2}{3}}\implies \cfrac{6\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{20}{3}} ~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{20}{3}-\cfrac{9}{2}\implies \stackrel{using ~~\stackrel{LCD}{6}}{\cfrac{(2\cdot 20)-(3\cdot 9)}{6}}\implies \cfrac{40-27}{6}\implies \cfrac{13}{6}\implies\blacktriangleright 2\frac{1}{6} \blacktriangleleft

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