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iVinArrow [24]
4 years ago
15

f. A restaurant chef prepares a tossed salad containing, on average, 5 vegetables per day. Find the probability that the salad c

ontains more than 7 vegetables on i) a given day and on ii)3 of the next 6 days?
Mathematics
1 answer:
gulaghasi [49]4 years ago
3 0

Answer:

Step-by-step explanation:

Given that a restaurant chef prepares a tossed salad containing, on average, 5 vegetables per day.

We can assume the number of vegetables used by the chef per day is

Poisson with parameter = mean = 5

We are to find the probability that the salad contains more than 7 vegetables on i) a given day and on ii)3 of the next 6 days?

a) P(no of vegetables >7) = 1-F(7) = 1-0.8666

=0.1334

b) For 6 days we can say each day is independent of the other

Prb( veg >3) for 6 days

= P(veg>3)^6

=(1-0.2650)^6\\=0.1576

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▹ Answer

Slope = -3

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y = mx + b

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therefore,

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5 0
3 years ago
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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
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Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

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\underline{x+3y=5}

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\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

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y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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Answer:

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Step-by-step explanation:

Let the other angles of the triangle are x, x degrees. Since the sum of angles in a  triangle is 180degrees, hence;

<A + <B+ <C = 180

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2x+70 = 180

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