We have been given that the diameter of a smaller circle is 7 km and the width of the circular path is 0.5 km. We are asked to find the area of the path.
The area of the path will be equal to area of larger circle minus area of smaller circle.
, where r represents radius of circle.
We know that radius is half the diameter, so radius of smaller circle would be 
km.
The radius of the larger circle will be radius of smaller circle plus width of the path that is 
km.
Therefore, the area of the circular path is approximately 11.8 square km.
I'm going to put this into vertex form, which is y=a(x-h)^2+k
To do this, you use completing the square. Start by subtracting 1 from each side
-1+y=x^2+2x
Then, divide b (2) by 2 and square it. Add that number to each side. (normally when you complete the square, you take out the gcf of the right side of the equation before you do this. Then, you would multiply (b/2)^2 by the gcf before adding it to the left side. Since there is no gcf, we do not have to worry about this)
2/2=1
1^2=1
-1+1+y=x^2+2x+1
Next, simplify the left side and factor the right side.
y=(x+1)^2
This is vertex form. a=1, h=-1, and k=0
The vertex is (h,k) so it is (-1,0)
hope this helps!
3/1 which simplified would be 3
Answer:
the possible coordinates are -9 and 3
Step-by-step explanation:
coordinates of B=(x2,y2)= (5,1)
Coordinates of A= (x1, y1)= (-3, z)
distance= 10 units
Formula: d=
substituting the values in the above formula
10=
10=
10=
10=
taking square root on both sides
100=
100-73=
=0
Answer: C.
It is the total cost for entertainment, facility rental, and cleaning.
For a 5 hour event organized by Marissa, we have a list of cost from different categories that would add up to the total for hosting the event. It includes the facility rental which is paid $150 per hour so for 5 hours it would be $750.
Next we have linens, food and table decorations that are charged according to the number of attendees at the event. Since the number of attendees is unknown here, we are going to skip everything which is effected by the number of attendees. Furthermore, we have musical entertainment and cleaning fee at a flat rate of $1800 and $250 respectively. So there are 3 things that we are sure about that they will stay constant despite the number of attendees and they are facility rental, musical entertainment and cleaning fee.
