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Vesna [10]
3 years ago
12

Help, please and thanks!

Mathematics
1 answer:
azamat3 years ago
7 0
B.
X-17=-5
Add 17 to both sides

-5+17=12
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Ray created the list of factors for 48 below.
brilliants [131]

Answer:

7

Step-by-step explanation:

also why is 78 there? a factor means in that range

3 0
3 years ago
Read 2 more answers
Hector found twice as many seashells as
MissTica
Hector = 2s or h/2
Sister = s


Equation: h/2 = s

Substitution: (20)/2 = s

10 = s


Hector’s sister found 10 seashells.
4 0
3 years ago
The government taxes a manufacturer $0.20 for a bottle of soda. The manufacturer raises the wholesale price an additional $0.60
alukav5142 [94]

Answer: $0.95

Step-by-step explanation:

Hi, to answer this question we simply have to add all amounts raised by the government, the manufacturer, and the retailer.

Mathematically speaking:

$0.20+$0.60+$0.15 = $0.95

So, a consumer pays $0.95 more per bottle of soda.

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
Creat a number that is less than 3 hundred thousands, 7 ten-thousands, 5 thousands, 2 hundreds, 1 ten.
frozen [14]
Ok to create a number less than 3 hundred thousand, 7 ten-thousands, 5 thousands, 2 hundreds and 1 ten, we need to know the place values of large numbers.
If it is less than 3 hundred thousand:
There would be 6 decimal places or: > 300,000

7 ten thousands:
70,000

5 thousand:
5,000

1 ten:
10

Join together all these numbers to get something like:
275,010

~I hope this helps!~ 
5 0
3 years ago
Can you please help? The question is in the picture picture. thank you
Naddika [18.5K]

Given:

The value is \dfrac{\sqrt{2}}{2}.

To find:

The values from the given options which are equal to the given value.

Solution:

We have,

\dfrac{\sqrt{2}}{2}

It can be written as:

\dfrac{\sqrt{2}}{2}=\dfrac{1}{\sqrt{2}}

From the standard trigonometric table, we get

\sin 30^\circ=\dfrac{1}{2}

\sin 45^\circ=\dfrac{1}{\sqrt{2}}

\cos 45^\circ=\dfrac{1}{\sqrt{2}}

\cos 60^\circ=\dfrac{1}{2}

\tan 30^\circ=\dfrac{1}{\sqrt{3}}

\tan 45^\circ=1

From the above values it is clear that the value of \sin 45^\circ and \cos 45^\circ are equal to \dfrac{1}{\sqrt{2}}.

Therefore, \sin 45^\circ and \cos 45^\circ and equal to \dfrac{\sqrt{2}}{2}. So, options B and C are correct.

4 0
3 years ago
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