Question

A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 32.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

Answer 1

Answer:

Average force exerted by the water on the blades is 1024 N

Explanation:

As we know that the force due to water jet is given by

$F = (v_{in} - v_{out})\frac{dm}{dt}$

here we know that

$v_{in} = 16 m/s$

$v_{out} = -16 m/s$

$\frac{dm}{dt} = 32 kg/s$

so here we will have

$F = (16 + 16)(32)$

$F = 1024 N$

Average force exerted by the water on the blades is 1024 N