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Bingel [31]
3 years ago
15

Pls help me with this problem!!

Physics
1 answer:
Olenka [21]3 years ago
7 0

Answer:

v = 19.6 m/s.

Explanation:

Given that,

The radius of the circle, r = 5 m

The time period of the ball, T = 1.6s

We need to find the ball's tangential velocity.

The formula for the tangential velocity is given by :

v=\dfrac{2\pi r}{T}

Putting all the values in the above formula

v=\dfrac{2\pi \times 5}{1.6}\\\\v=19.6\ m/s

So, the tangential velocity of the ball is 19.6 m/s. Hence, the correct option is (c).

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Calculate the minimum wavelength (λ0) for the continuous spectrum of X-rays emitted when.. a) 30-kV electrons strike a cobalt (C
Sholpan [36]

Explanation:

The relationship between the wavelength and the potential difference V is given by :

\lambda=\dfrac{h}{\sqrt{2me}}\times \dfrac{1}{\sqrt{V}}

Putting the values of known parameters,

\lambda=\dfrac{12.28}{\sqrt{V} }\times 10^{-10}\ m

(a) V=30\ kV=30000\ V

\lambda=\dfrac{12.28}{\sqrt{30000} }\times 10^{-10}\ m

\lambda=7.08\times 10^{-12}\ m

(b) V=60\ kV=60000\ V

\lambda=\dfrac{12.28}{\sqrt{60000} }\times 10^{-10}\ m

\lambda=5.01\times 10^{-12}\ m

Hence, this is the required solution.

4 0
4 years ago
If April launched a water balloon directly upwards with a speed of 40 m/s, how high would it be after 6 seconds? Use 10 m/s​
Volgvan

Answer:

495m

Explanation:

ANSWER

u

stone

=10m/s (initial velocity of stone)

t=11s

∴H=−ut+

2

1

gt

2

(H=height of baloon)

H=−10×11+

2

1

×10×121=605−110=495m

3 0
4 years ago
Denis throws a ball downward at an initial speed of 15 m/s from the top of a cliff. (a)
Gennadij [26K]

Answer:

Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

Explanation:really sorry if it wrong,i mean reallyyyyy

4 0
3 years ago
The purpose of a fuse or circuit breaker is _____.
ExtremeBDS [4]
What a sloppy question ! The purpose of a fuse or circuit breaker is to shut down the circuit when current reaches a magnitude indicating danger due to a serious malfunction. When current IS flowing in the circuit, it's always flowing at the same speed.
3 0
3 years ago
Read 2 more answers
A basketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance L = 5.0
FromTheMoon [43]

Answer:

v_0 =1.71

Explanation:

the parabolic movment is described by the following equation:

y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2

where y is the height of the ball, a is the angle of launch, v_0 the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2

Finally, solving for v_0, we get:

v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}

v_0 =1.71

4 0
4 years ago
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