Answer:
e. 400 Hz
Explanation:
In closed organ pipe, only odd harmonics of fundamental note is possible .
The fundamental frequency is 200 Hz . Then other overtones will be having following frequencies .
200 x 3 , 200 x 5 , 200 x 7 , 200 x 9 etc
600 Hz , 1000 Hz , 1400 Hz , 1800 Hz .
Frequency not possible is 400 Hz .
Answer:Principle of rectilinear propagation of light
Explanation:Principle of rectilinear propagation of light
Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.
The sweater has a tendency to attract electrons.
The leather jacket has a lower tendency to attract electrons than the sweater.
Explanation:
The sweater and the leather jackets are made up of distinct fabrics that based on their minutest particles called an atom.
An atom is made up of sub-atomic particles of protons, neutrons and electrons.
- Electrons occupies the bulk volume of the atom and they are easily lost in atoms that are big. They are negatively charged.
- Protons are positively charged and are very difficult to lose. They occupy the tiny nucleus with neutrons.
- A body that becomes negatively charged will be said to have a hihg tendency to attract electrons. Normally atoms are electrically neutral. When additional electrons are added to them, they become negatively charged.
- In this case, the sweater has a high affinity for electrons and it will attract the ones on the leather jacket.
- The leather jacket has a low tendency to attract electrons than the sweater and it will lose some of its electrons to the sweater.
Learn more:
Protons, neutrons and electrons brainly.com/question/2757829
#learnwithBrainly
Carbon: C, 12.011, 6, 12
Oxygen: O, 8, 8, 8, 16
Boron: B, 10.811, 5, 5, 11
Answer:
5.1*10^3 J/m^3
Explanation:
Using E = q/A*eo
And
q =75*10^-6 C
A = 0.25
eo = 8.85*10^-12
Energy density = 1/2*eo*(E^2) = 1/2*eo*(q/A*eo)^2 = [q^2] / [2*(A^2)*eo]
= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]
= 5.1*10^3 J/m^3
