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1 answer:
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Answer:
Here's what I get.
Step-by-step explanation:
Assume the diagram is like the one below.
Segments AB, BC, and CH are transversals to the sides of the pool table.
BC is also a transversal to AB and CH.
a. Angles we can be sure about
∠ABC — interior opposite angles of transversal BC
∠CBH — interior opposite angles of transversal BC
∠BHC — interior angles of triangle BHC
∠ABK — alternate exterior angles of transversal BC
∠CHG — complementary to ∠CGH
b. Sets of congruent angles
∠ABC ≅ ∠BCH = 66° — interior opposite angles of transversal BC
∠CBH ≅ ∠BCE = 57° — interior opposite angles of transversal BC
∠BHC ≅ ∠GCH = 57° — interior opposite angles of transversal CH
∠ABK ≅ ∠GCH = 57° — alternate exterior angles of transversal BC
One set of congruent angles is {∠ABC, ∠BCH}
Another set is {∠ABK, ∠BCE, ∠BHC, ∠CBH, ∠GCH}
c. Alternate interior angles
Alternate interior angles are a pair of angles on the inner sides of the parallel lines but on opposite sides of the transversal.
The sets of alternate interior angles are {∠ABC, ∠BCH}, {∠ ABC, ∠BCD} {∠BCE, ∠CBH}, {∠CHJ, ∠GCH}
d. Corresponding angles
Corresponding angles are a pair of angles on the same side of parallel lines and on the same side of the transversal.
The diagram has no corresponding angles.
Answer:
y= -x+b
Step-by-step explanation:
hello :
the slope for the line : - x+y=2 is 1 because -x+y = 2 means y= 1x+2
all lines perpendicular to the line -x+y=2 have equation : y = ax+b
when : a×(1) = -1 so : a=-1
an equation is : y= -x+b
look the graph for the line : -x+y=2 (color red) and some lines
perpendicular to this line
