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3 years ago

38=x+10+9-3I don't get this question

Mathematics

1 answer:

Lilit [14]3 years ago

4 0

Answer:

so is that all it says, if its not thats not a question because its already answered

Step-by-step explanation:

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What does it mean when there are variables on top of each other in parentheses in statistics?

Ilya [14]

It's a combination:
$\left( {{n} \atop {k}}\right)\equiv C(n,k)=\dfrac{n!}{(n-k)!k!}$

4 0

3 years ago

Find the equation of the linear function represented by the table below in slope intercept form.

grigory [225]

Answer:

y = -3x - 2

Step-by-step explanation:

slope (m) = (-8 - -5) / (2 - 1) ... difference of y/difference of x

m = -3

y = mx + b

y = -3x + b

for (3,-11) b = y + 3x = -11 + 3x3 = -2

equation: y = -3x - 2

5 0

3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Which data collections show bias? Check all that apply.

V125BC [204]

Answer:

An insurance company polls drivers of sports cars to find their average number of tickets.

Step-by-step explanation:

It’s bias because they’re only polling people with sports cars

7 0

2 years ago

Read 2 more answers

Two boards are resting against each other to form an isosceles triangle with the ground as shown in the diagram. What is the hei

stiv31 [10]

Answer:

ygyvyvububububububububububububububububububububububububububububububububububububinininininininininubububyvyctctcrxrxrcrct vvtvybububunininininuninububububububbuub

Step-by-step explanation:

778885542123456678900098776554331112345678900

5 0

3 years ago

38=x+10+9-3I don't get this question​

38=x+10+9-3I don't get this question