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3 years ago

38=x+10+9-3I don't get this question

Mathematics

1 answer:

Lilit [14]3 years ago

4 0

Answer:

so is that all it says, if its not thats not a question because its already answered

Step-by-step explanation:

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Beth purchased a computer, and its value depreciated exponentially each year. Beth will sketch a graph of the situation, where x

Katyanochek1 [597]

What is x?

It is the number of years since purchase. Can this be negative?

NO! Years cannot be negative. So we disregard negative x-axis.

What is y?

It is the value of the computer at that year. A computer starts off with a positive value (y axis) and depreciates to 0 after some years. Can this be negative?

NO! At 0 value, the computer is worth nothing! There is nothing known as <em>negative </em>value. So we disregard negative y-axis.

The graph that Beth will sketch will have to be in the 1st quadrant (positive x-axis & positive y-axis).

ANSWER: Quadrant I only

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3 years ago

Differential Equations Problem

fgiga [73]

Answer:

$y=\frac{t^2e^{2t}}{3}+ce^{2t}$

Step-by-step explanation:

We have given differential equation $\frac{dy}{dt}-2y=t^2e^{2t}$

We know that linear differential equation is given by $\frac{dy}{dt}+Py=Q$

On comparing with standard equation P = -2 and Q= $t^2e^{2t}$

Now integrating factor $IF=e^{-Pdt}$

$IF=e^{-2dt}=e^{-2t}$

Now solution of differential equation is given by

$y\times IF=\int\ IF\times Q\ dt$

$y\times e^{-2t}=\int\ e^{-2t}\times t^2e^{2t}\ dt$

$y\times e^{-2t}=\frac{t^2}{3}+c$

$y=\frac{t^2e^{2t}}{3}+ce^{2t}$

7 0

3 years ago

Why is the numbers 2,-3,5,0,-1 a integer number

Ivan

Because they dont have variables

7 0

2 years ago

Find and interpret the mean absolute deviation of the data. Round your answer to the nearest tenth, if necessary. The mean absol

SSSSS [86.1K]

Answer list the data sets

Step-by-step explanation:

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2 years ago

P( x) =x^3-6x^2-5x-14 What is the remainder R when the polynomial p(x) is divided by (x-7)

Igoryamba

Answer:

The remainder is zero

Step-by-step explanation:

To find the remainder we will use the long division

$\frac{x^{3}-6x^{2}-5x-14}{x-7}=x^{2}\frac{x^{2}-5x-14 }{x-7}$ ⇒(1)

$\frac{x^{2}-5x-14}{x-7}=x\frac{2x-14}{x-7}$ ⇒(2)

$\frac{2x-14}{x-7}=2$ ⇒(3)

From (1) , (2) and (3)

The quotient of the long division is $x^{2}+x+2$ and no remainder

So the remainder is zero

* If you want to check your answer Multiply the quotient by the divisor

$(x^{2}+x+2)(x-7)=x^{3}-6x^{2}-5x-14$

8 0

3 years ago

38=x+10+9-3I don't get this question​

38=x+10+9-3I don't get this question