Which point gives the vertex of ƒ(x) = –x2 + 4x – 3?
1 answer:
Answer:
The vertex is (2,1)
Step-by-step explanation:
ƒ(x) = –x^2 + 4x – 3
Factor out the negative
= -(x^2 -4x+3)
Factor
What 2 numbers multiply to +3 and add to -4
-3*-1 = 3
-3+-1 = -4
f(x) = -( x-3)(x-1)
Find the zeros
0 = -( x-3)(x-1)
0 = x-3 0 = x-1
x=3 x=1
The x value of the vertex is 1/2 way between the two zeros
(3+1)/2 = 4/2 =2
To find the y value, substitute x=2 in
f(2) = -( 2-3)(2-1)
=-(-1)(1) = 1
The vertex is (2,1)
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