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Step2247 [10]
3 years ago
14

40x8=. Tens x 8 =. Tens =

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0
40x8=320

That’s all I can answer I’m not really sure I understand the rest of the question
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you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
1 year ago
The slope of the line below is 2. Use the coordinates of the labeled point to find a point-slope equation of the line.
stich3 [128]

Answer:

Option: D is the correct answer.

The equation of line in point-slope form is given by:

y-9=2(x-1)

Step-by-step explanation:

We know that the point-slope equation of a line is given by:

y-b=m(x-a)

where (a,b) is the point from which the line passes and m is the slope of the line.

Here we are given that:

The line passes through (1,9) and slope of the line is given to be 2.

Hence,

(a,b)=(1,9) and m=2

Hence, the equation of line is given by:

y-9=2(x-1)

Therefore, the point slope intercept equation of the line is: D

3 0
2 years ago
a number, half of that number, and one-third of that number are added. the result is 22. what is the number?
tiny-mole [99]
Let the number be x.

Half of that number  =  x / 2
One third of the number  =  x / 3

=  x / 2 + x / 3 = 22.  LCM  =  6.

= (3x + 2 x) / 6  = 22.

5x / 6 = 22.      Cross multiply

5x = 6 * 22.

5x = 132      Divide both sides by 5.

x =  132 / 5

x = 26.4

The number is 26.4.  Cheers.
5 0
3 years ago
Determine the slope and y-intercept of each line.
Zarrin [17]

Answer:

Step-by-step explanation:

y + 2 = 4(x - 1)

y + 2 = 4x - 4

y = 4x - 4 - 2

y = 4x - 6

Comparing with y = mx + c

Where m is the slope and c the intercept

Slope m = 4 and c = -6

6 0
3 years ago
What is the midpoint between (5.2).(-4,-3)
Murrr4er [49]

Answer:

Step-by-step explanation:

(5-4)/2 = 1/2

(2-3)/2 = -1/2

(1/2, -1/2)

4 0
3 years ago
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