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Factor
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using the AC method.
Tap for fewer steps...
Factor
x
2
−
x
−
2
using the AC method.
Tap for more steps...
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Remove unnecessary parentheses.
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I honestly dont know, the only idea I have is to divide 1800 by 4 to see how much.
Cos A) 16/20 or 4/5
Tan A) 12/16 or 3/4
Sin A) 12/20 or 3/5
√-1=i
13-√-18=
13-√(-1)(18)=
13-(√-1)(√18)=
13-(i)(3√2)=
13-3i√2
If one of the numbers we multiply (factors) has zeros at the end, and the other isn't a fraction: all those zeros will stay in the product.
But there might be additional zeros if the other numbers in the factors (the numbers which aren't 0) mupliply to "end" in zero and this is the case here:
8*5=40.
so the product will be 40 and the zeros of the 5000:
40 000
the number of zeros in the product will be bigger than the number of zeros in the factors if the non-zero parts of the fractions multiply to a number with 0 at the end.
